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1 year ago

HELPPPPPPPPPPPP (-12)^3:8^3

Mathematics

1 answer:

Nadusha1986 [10]1 year ago

8 0

Answer:

-1728:512

Step-by-step explanation:

(-12)³ = -1728

8³ = 512

ratio is -1728:512

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Radius= 4cm. find the area and diameter of the circle

Bezzdna [24]

<h3>given:</h3>

radius= 4 cm

the area and the diameter of the circle.

<h3>solution:</h3><h3>diameter:</h3>

$d = 2r$

$d = 2 \times 4$

$d = 8 \: cm$

therefore, the diameter of the circle is 8 centimeters.

$a = \pi {r}^{2}$

$a = \pi \times {4}^{2}$

$a = 50.26548 \: {cm}^{2}$

$a = 50.27 \: {cm}^{2}$

hence, the area of the circle is 50.27 square centimeters.

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3 years ago

19. Which is the suitable identity used to evaluate 9992 ?

andrew11 [14]

Answer:

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(1000-1)^2

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3 years ago

A car has a velocity of 25 m/s and a mass of 3500 kg. What is the cars momentum?

gtnhenbr [62]

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Step-by-step explanation:

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2 years ago

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If f and t are both even functions, is the product ft even? If f and t are both odd functions, is ft odd? What if f is even and

Natali5045456 [20]

Answer:

(a) If f and t are both even functions, product ft is even.

(b) If f and t are both odd functions, product ft is even.

Step-by-step explanation:

Even function: A function g(x) is called an even function if

$g(-x)=g(x)$

Odd function: A function g(x) is called an odd function if

$g(-x)=-g(x)$

(a)

Let f and t are both even functions, then

$f(-x)=f(x)$

$t(-x)=t(x)$

The product of both functions is

$ft(x)=f(x)t(x)$

$ft(-x)=f(-x)t(-x)$

$ft(-x)=f(x)t(x)$

$ft(-x)=ft(x)$

The function ft is even function.

(b)

Let f and t are both odd functions, then

$f(-x)=-f(x)$

$t(-x)=-t(x)$

The product of both functions is

$ft(x)=f(x)t(x)$

$ft(-x)=f(-x)t(-x)$

$ft(-x)=[-f(x)][-t(x)]$

$ft(-x)=ft(x)$

The function ft is even function.

(c)

Let f is even and t odd function, then

$f(-x)=f(x)$

$t(-x)=-t(x)$

The product of both functions is

$ft(x)=f(x)t(x)$

$ft(-x)=f(-x)t(-x)$

$ft(-x)=[f(x)][-t(x)]$

$ft(-x)=-ft(x)$

The function ft is odd function.

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2 years ago