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2 years ago

Emma gets paid $5,000 per month.

Mathematics

1 answer:

tekilochka [14]2 years ago

7 0

Answer:

25 percent.

Step-by-step explanation:

1,000 would be 20% of 5,000

250 is 5% of 5,000

20+5=25

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Solve a^3 • (-a^2b)^4

Varvara68 [4.7K]

Answer:/?idk

Step-by-step explanation:

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2 years ago

16. The number of miles a car can be driven depends on the number of gallons in its tank. The

valentina_108 [34]

Answer:

Step-by-step explanation:

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2 years ago

Solve for p.

Vinil7 [7]

Answer:

p = -2

Step-by-step explanation:

5p - 10 = + 4(1 + 3p)

first get rid of the bracquetes:

5p - 10 = + 4*1 + 4*3p

5p - 10 = + 4 + 12p

subtract left and right of = sign by 5p

5p -5p - 10 = + 4 + 12p -5p

0 - 10 = + 4 + (12p -5p)

subtract left and right of = sign by 4

-10 -4 = 4 -4 + ( 7p )

re arrange

7p + 0 = -14

divide left and right of = sign by 7

7/7 p = -14/7

p = -2

5 0

3 years ago

Read 2 more answers

At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more

I am Lyosha [343]

Answer:

The probability is $P( X \le 4 ) = 0.0054$

Step-by-step explanation:

From the question we are told that

The percentage that are on time is p = 0.76

The sample size is n = 11

Generally the percentage that are not on time is

$q = 1- p$

$q = 1- 0.76$

$q = 0.24$

The probability that no more than 4 of them were on time is mathematically represented as

$P( X \le 4 ) = P(1 ) + P(2) + P(3) + P(4)$

=> $P( X \le 4 ) = \left n } \atop {}} \right.C_1 p^{1} q^{n- 1} + \left n } \atop {}} \right.C_2p^{2} q^{n- 2} + \left n } \atop {}} \right.C_3 p^{3} q^{n- 3} + \left n } \atop {}} \right.C_4 p^{4} q^{n- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{11- 1} + \left 11 } \atop {}} \right.C_2p^{2} q^{11- 2} + \left 11 } \atop {}} \right.C_3 p^{3} q^{11- 3} + \left 11 } \atop {}} \right.C_4 p^{4} q^{11- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{10} + \left 11 } \atop {}} \right.C_2p^{2} q^{9} + \left 11 } \atop {}} \right.C_3 p^{3} q^{8} + \left 11 } \atop {}} \right.C_4 p^{4} q^{7}$

$= \frac{11! }{ 10! 1!} (0.76)^{1} (0.24)^{10} + \frac{11!}{9! 2!} (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!} (0.76)^{3} (0.24)^{8} + \frac{11!}{7!4!} (0.76)^{4} (0.24)^{7}$

$P( X \le 4 ) = 0.0054$

4 0

2 years ago

!!!!!!!!HELP PLEASE!!!!!!!! In ΔSTU, SU = 18 and TU = 13. Find m∠T to the nearest tenth of a degree.

tatyana61 [14]

We can use a trig function to find the measure of angle T.

tan(T) = 18/13

Take the archtangent on both sides since we are searching for an angle.

arctan(tan T) = arctan(18/13)

T = 54.16°

The measure of angle T is 54.16°.

4 0

3 years ago