Question

The diameter of a large lawn ornament in the shape of a sphere is 16 inches. What is the approximate volume of the ornament? Use 3.14 for π . Round to the nearest tenth of a cubic inch.

Answer 1

Answer: $2143.6\ in.^3$

Step-by-step explanation:

Given: The diameter of a large lawn ornament in the shape of a sphere = 16 inches.

Then, the radius of ornament =$\frac{16}{2}=8$ inches.

We know that the volume of a sphere is given by :-

$\text{Volume}=\frac{4}{3}\pi r^3$, where r is the radius of a sphere.

Now, the volume of the ornament is given by :-

$\text{Volume}=\frac{4}{3}(3.14) (8)^3\\\\\Rightarrow\text{Volume}=\frac{4}{3}\times3.14\times512=2143.57333333\approx2143.6\ in,^3$

Hence, the approximate volume of the ornament $=2143.6\ in.^3$

Answer 2

volume = 4/3 x pi x r^3

r = 16/2=8

v = 4/3 x 3.14 x 8^3 = 2143.573 = 2,143.6 cubic inches