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skad [1K]
2 years ago
10

The diameter of a large lawn ornament in the shape of a sphere is 16 inches. What is the approximate volume of the ornament? Use

3.14 for π . Round to the nearest tenth of a cubic inch.
Mathematics
2 answers:
Dvinal [7]2 years ago
7 0

Answer: 2143.6\ in.^3

Step-by-step explanation:

Given: The diameter of a large lawn ornament in the shape of a sphere = 16 inches.

Then, the radius of ornament =\frac{16}{2}=8 inches.

We know that the volume of a sphere is given by :-

\text{Volume}=\frac{4}{3}\pi r^3, where r is the radius of a sphere.

Now, the volume of the ornament is given by :-

\text{Volume}=\frac{4}{3}(3.14) (8)^3\\\\\Rightarrow\text{Volume}=\frac{4}{3}\times3.14\times512=2143.57333333\approx2143.6\ in,^3

Hence, the approximate volume of the ornament =2143.6\ in.^3

fiasKO [112]2 years ago
7 0

volume = 4/3 x pi x r^3

r = 16/2=8

v = 4/3 x 3.14 x 8^3 = 2143.573 = 2,143.6 cubic inches

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Answer:

C) 4√3

Step-by-step explanation:

The given triangle is an equilateral triangle. BD is angle bisector.

Triangle BCD is a 30-60-90 degree triangle in the ration of 1:√3:2

Here we are given BC, that is highest length of the side.

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3 years ago
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Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y
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Answer: -1.0018*10^42

Step-by-step explanation:

The Euler Method in numerical analysis is used to approximate the solution to an initial value problem using the tangent line to the solution curve through the (x0,y0) to obtain such approximations.

The euler method equation is:

Yn+1 = Yn + h*f(Xn,Yn)

Where n = number of steps, h = Xn+1 - Xn, f(Xn,Yn) is the slope of the curve at (Xn,Yn).

Variables given in the equation

Y(X=0) = 9,

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B

For the first step, n = 0 in the euler equation. Therefore we have:

Y1 = Y0 + h*f(X0,Y0)

Substituting the Y0 = 9 and X0 = 0 into the function f(X,Y) = X^2*Y - 12*Y^2 = 0^2*9 - 12*9^2 = -972.

Therefore Y1 = 9 + 0.2*(-972) = -185.4.

For n = 1

Repeating the same step with X1 = X0 + h = 0 + 0.2 = 0.2,

Y1 = -185.4,

h = 0.2.

Substitute the variables into the equation Y2 = Y1 + h*f(X1,Y1) and f(X1,Y1) = X1^2*Y1 - 12*Y1^2

Y2 = -82682.4672.

Continue the iterations following the steps above till the result is reached.

The summary of the iteration.

When n = 0, X = 0, Y = -185.4

When n = 1 , X = 0.2, Y = -82682.4672

When n = 2 , X = 0.4, Y = -1.6407*10^10

When n = 3, X = 0.6, Y = -6.4609*10^20

When n = 4, X = 0.8, Y = -1.0018*10^42

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