If light travels at 10,000 km in 3.0 x 10² seconds,

Mathematics

1 answer:

eduard1 year ago

4 0

Answer:

1000xm

Step-by-step explanation:

1 meter = 3.2808 feet, hence. 9.8424 x 10^8 feet in 1 second. 1 foot in x seconds. hence it takes 1 / (9.8424 x 10^8) = 0.10168 x 10^(-8) seconds. ➡️1km = 1000xm⬅️

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Cost to store: $140<br><br> Markup: 25%

anastassius [24]

The actual cost to the store = $140
Percentage of markup = 25%
Amount of markup in cost = (25/100) * 140 dollars
= 35 dollars
Then
Sell price in the store = (35 + 140) dollars
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So the sell price of the product at the store after addition of the markup price will be $175.

7 0

3 years ago

Find the measure of each interior angle and each exterior angle of a regular 20-gon (a twenty-sided polygon).Measure of each int

ra1l [238]

Given a regular 20-gon ( a 20 sided polygon )

The measure of each interior angle will be given by:

$\frac{(n-2)}{n}\cdot180$

where n is the number of sides

Substitute with n = 20

So, the measure of each interior angle =

$\frac{20-2}{20}\cdot180=\frac{18}{20}\cdot180=162$

The sum of exterior angles = 360

So, the measure of each exterior angle = 360/20 = 18

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1 year ago

b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.

Ainat [17]

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ $2x$