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Annette [7]
2 years ago
14

a group of students was randomly divided into two subgroups. one subgroup took a test in the morning, and the other took the sam

e test in the afternoon. this table shows the results. compare the probability that a student will pass the test in the morning with the probability that a student will pass the test in the afternoon. draw a conclusion based on your results.

Mathematics
1 answer:
Tom [10]2 years ago
8 0

The conclusion is P(pass l morning) = 0.56

P(pass l afternoon) = 0.72

Conclusion: a student taking the test in the afternoon has a greater probability of passing than a student taking the test in the morning.

<h3>What are the probabilities?</h3>

Probability is the odds that a random event would happen. The odds that the event would happen lies between 0 and 1. The closer the probability is to one, the more likely it is for the event to happen.

P(pass l morning) = number of students who took the test in the morning and passed / total number of students that took the exam in the morning

28 / 50 =  0.56

P(pass l afternoon) = number of students who took the test in the afternoon and passed / total number of students that took the exam in the afternoon  = 36 / 50 = 0.72

To learn more about probability, please check: brainly.com/question/13234031

#SPJ1

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3 years ago
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Answer:

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3 years ago
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2.The number of tickets sold to a play for each showing is 78, 84, 87, 80, 91, 95, and 80.
Luden [163]

Answer:

Min =78

The maximum is :

Max = 95

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

Median =84

Now we can find the quartile 1 we analyze the first 4 values  78, 80,80, 84 and the first quartile would be:

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Now we can find the quartile 3 we analyze the last 4 values  84,87, 91, 95 and the third quartile would be:

Q_3= \frac{87+91}{2}=89

And finally the 5 number summary would be:

Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96

Step-by-step explanation:

We have the following data given:

78, 84, 87, 80, 91, 95, and 80.

The first step is order the dataset on increasing way and we got:

78, 80,80, 84,87, 91, 95

We can begin finding the minimum value and for this case is:

Min =78

The maximum is :

Max = 95

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

Median =84

Now we can find the quartile 1 we analyze the first 4 values  78, 80,80, 84 and the first quartile would be:

Q_1= \frac{80+80}{2}= 80

Now we can find the quartile 3 we analyze the last 4 values  84,87, 91, 95 and the third quartile would be:

Q_3= \frac{87+91}{2}=89

And finally the 5 number summary would be:

Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96

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Answer:

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If the nature of the problem allows distributing decimal portions of N, then every receiver gets exactly the same amount N/m.

But things are different when the division must be an integer number. For example, if we wanted to divide gifts, we cannot give partial gifts. So the correct division is a matter of the study of integer numbers.

If N is divisible by m, i.e. there is no remainder in the division, then each element will receive N/m gifts. But what if they are not divisible? We must divide and take the integer part of the division and discard the remainder

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Answer. Each classroom received 120 gifts and the hospital received 12 gifts

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3 years ago
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