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hjlf
2 years ago
11

Question 19 of 25 f(x)=√x-6. Find the inverse of f(x) and its domain.

Mathematics
1 answer:
Gekata [30.6K]2 years ago
5 0

Answer:

f¯¹(x)=x²+12x+36

Step-by-step explanation:

f(x) =  \sqrt{x}  - 6 \\ substitute \: y \: for \: f {}^{ - 1} (x) \\ y =  \sqrt{x}  - 6 \\ interchange \: x \: and \: y \\ x =  \sqrt{y}  - 6 \\ swap \: the \: side \: of \: the \: equation \\  \sqrt{y }  - 6 = x \\ move \: the \: constant \: to \: the \: right \: hand \: side \\   \sqrt{y}  = x + 6 \\ square \: both \: sides \: of \: the \: equation \\ y = x {}^{2}  + 12x + 36 \\ substitute \: f \frac{}{ -1} (x) \: for \: y \\ f {}^{ - 1} (x) = x {}^{2}  + 12x + 36 \\ domain \: x∈R

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If a bacteria population starts with 100 bacteria and doubles every three hours, then the number of bacteria after t hours is n
natali 33 [55]

Answer:

f^{-1}=3ln_2(\frac{t}{100})

f^-1 represents the number of hours the bacteria developed

Step-by-step explanation:

f(t) = 100 \cdot  2^\frac{t}{3}

To find inverse of a function , replace f(t) with y

y= 100 \cdot  2^\frac{t}{3}

replace t with y and y with x

x= 100 \cdot  2^\frac{y}{3}

solve for y

divide both sides by 100

\frac{x}{100} =2^\frac{y}{3}

take ln on both sides

ln \frac{x}{100} =\frac{y}{3}ln 2

divide both sides by ln

ln_2(\frac{x}{100}) =\frac{y}{3}

multiply by 3 on both sides

y=3ln_2(\frac{x}{100})

Replace x with t  and y with f^-1

f^{-1}=3ln_2(\frac{t}{100})

f^-1 represents the number of hours the bacteria developed

7 0
3 years ago
Write the quadratic equation whose roots are
maks197457 [2]
The quadratic equation y = ax^2 +bx+c can be written in the form:
y = a(x-p)(x-q)
Where p and q are the roots of the equation.
Given p = 4, q = -2, a = 3, the quadratic will look like this:
y = 3(x-4)(x+2)
Finally, distribute and combine like terms to put it in standard form.
y = 3(x^2 - 4x+2x -8) \\  \\ y = 3(x^2 -2x-8) \\  \\ y = 3x^2 -6x -24
5 0
3 years ago
There are "n" delicious sweets in the bag. You know that 6 of them are orange and the rest are yellow. Hannah takes a random swe
nikitadnepr [17]
At the point when Hannah takes her first sweet from the sack, there is a 6/n chance it is orange. 
This is because that there are 6 orange desserts and n desserts altogether. 
When Hannah takes out her second sweet, there is a 5/(n-1) chance that it is orange. 
This is because there are just 5 orange desserts let alone for an aggregate of n-1 desserts. 
The possibility of getting two orange desserts in succession is the main likelihood increased by the second one: 6/n x 5/n–1 
The question lets us know that the shot of Hannah getting two orange desserts is 1/3. 
So: 6/n x 5/n–1 = 1/3 
Now, rearrange this problem. 
(6x5)/n(n-1) = 1/3 
This gets to be: 
30/(n² – n) = 1/3 
Times by 3 on both sides: 
90/(n² – n) = 1 
What's more, doing likewise with (n² – n): 
So (n² – n) = 90 
Our answer is: n² – n – 90 = 0
3 0
3 years ago
Please need help on this
Ronch [10]

Ray FM has terminal point F, so that will be the first letter of the name. The second letter of the name can be any of the points to the left of F on the line:

... D, L, M, P, K

Appropriate choices are ...

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8 0
3 years ago
The sum of the ages of Kristen and Ben is 32. Four years ago Kristen was twice as old as Ben. How old are they both now?
Elan Coil [88]

Let us say that:

K = age of Kristen

B = age of Ben

 

From the problem, we make the equations:

eqtn 1: K + B = 32

eqtn 2: (K – 4) = 2 (B – 4)

 

Simplifying eqtn 2:

K – 4 = 2 B – 8

K = 2 B – 4

 

Plugging in this to eqtn 2:

(2 B – 4) + B = 32

3 B – 4 = 32

3 B = 36

B = 12

 

From eqtn 2:

K = 2 B – 4 = 2 (12) – 4 = 20

 

So Kristen is 20 while Ben is 12.

5 0
3 years ago
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