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babymother [125]
2 years ago
8

Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 66 kmh faster than the othe

r. If the two planes are 10,716 kilometers apart after 6 hours, what is the rate of each plane
Mathematics
1 answer:
goldfiish [28.3K]2 years ago
3 0

Answer:

  • The rate of planes: 926 km/h and 860 km/h

=========================

<h3>Given</h3>

  • Two planes travel in opposite directions,
  • One plane travels 66 km/h faster than the other,
  • The distance between the two planes after 6 hours is 10716 km.

<h3>To find</h3>

  • The rate of of each plane

<h3>Solution</h3>

The distance traveled by two planes in an hour is:

  • 10716/6 = 1786 km/h

Let the rate of one plane be x, then the other plane's rate is x - 66.

The sum of two rates is the distance traveled in one hour:

  • x + x - 66 = 1786
  • 2x - 66 = 1786
  • 2x = 1786 + 66
  • 2x = 1852
  • x = 1852/2
  • x = 926

So the rate of one plane is 926 km/h and of the other plane is:

  • 926 - 66 = 860 km/h
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masya89 [10]

Answer:  y = 3x + 1

<u>Step-by-step explanation:</u>

The equation is in Slope-Intercept format: y = mx + b      where

  • m is the slope <em>(difference in y's over difference in x's)</em>
  • b is the y-intercept   <em>(value of y when x = 0)</em>

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\\\text{Let }(x_1,y_1)=(0,1)\quad \text{and}\quad \text{let }(x_2, y_2)=(1,4)\quad then\\\\m=\dfrac{4-1}{1-0}=\dfrac{3}{1}=3

b = 1     <em>refer to the table that shows y = 1 when x = 0</em>

Now input m = 3 and b = 1 into the Slope-Intercept formula:

y = 3x + 1

8 0
3 years ago
I run a 10km race in 56 minutes.what is my average speed in kilometres per minute
Luden [163]

Hey there! I'm happy to help!

You ran a 10 kilometer race in 56 minutes (good job!). To find how much you ran in 1 minute, you simply divide by 56.

10/56=0.178571428

Therefore, you ran around 0.18 km/minute.

Have a wonderful day! :D

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3 years ago
Solve log2(x) – log2(3) = 2.
Lynna [10]

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Step-by-step explanation:

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3 0
3 years ago
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mel-nik [20]

Answer: x= 2.5, y = 10

Step-by-step explanation:

<u><em>I'm going to assume that these photocopies are proportional in relations to each other.</em></u>

If they're proportional, you can set up two proportions:

1) \frac{x}{5} =\frac{3}{6} \\\\2) \frac{5}{y} =\frac{3}{6}

And cross-multiply:

1) 6x = 5*3 \\\\2) 3y = 5*6

Then solved for x and y:

1) 6x = 15\\x=\frac{15}{6} =\frac{5}{2} =2.5 \\\\2) 3y = 30\\y=\frac{30}{3} =10

5 0
3 years ago
(143(5) + 67)5-----------Anybody???:)
Vikentia [17]
<span>(143(5) + 67)5
Multiply 143 by 5
(715 + 67)5
Add the numbers inside the parenthesis(715 and 67).
(782)5
Multiply 782 by 5.
Final Answer: 3,910</span>
6 0
3 years ago
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