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babymother [125]
2 years ago
8

Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 66 kmh faster than the othe

r. If the two planes are 10,716 kilometers apart after 6 hours, what is the rate of each plane
Mathematics
1 answer:
goldfiish [28.3K]2 years ago
3 0

Answer:

  • The rate of planes: 926 km/h and 860 km/h

=========================

<h3>Given</h3>

  • Two planes travel in opposite directions,
  • One plane travels 66 km/h faster than the other,
  • The distance between the two planes after 6 hours is 10716 km.

<h3>To find</h3>

  • The rate of of each plane

<h3>Solution</h3>

The distance traveled by two planes in an hour is:

  • 10716/6 = 1786 km/h

Let the rate of one plane be x, then the other plane's rate is x - 66.

The sum of two rates is the distance traveled in one hour:

  • x + x - 66 = 1786
  • 2x - 66 = 1786
  • 2x = 1786 + 66
  • 2x = 1852
  • x = 1852/2
  • x = 926

So the rate of one plane is 926 km/h and of the other plane is:

  • 926 - 66 = 860 km/h
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Travka [436]
<h3>Answer: width is 10 feet</h3>

=========================

Work Shown:

L = length = 18

W = width = unknown

P = perimeter of rectangle = 56

P = L+L+W+W

P = 2L+2W

P = 2*18+2W ... plug in given length

P = 36+2W

36+2W = P

36+2W = 56 ... plug in given perimeter

36+2W-36 = 56-36 ... subtract 36 from both sides

2W = 20

2W/2 = 20/2 ... divide both sides by 2

W = 10

This rectangle is 10 ft by 18 ft.

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note: this assumes that there is no bit of fencing that goes to waste, there are no gaps, or there are no overlapping portions.

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