Answer:
ooooo
Step-by-step explanation:
Since the width is the smaller value, make the width=x. That would make the length=2x-3. Area=length*width. Substitute your variables and known values into the equation. 14=(2x-3)(x). Distribute the x to give you
![14=2 x^{2} -3x](https://tex.z-dn.net/?f=14%3D2%20x%5E%7B2%7D%20-3x)
. Set the equation equal to 0 giving you
![2 x^{2} -3x-14=0](https://tex.z-dn.net/?f=2%20x%5E%7B2%7D%20-3x-14%3D0)
. Factor the equation to give you
![(2x-7)(x+2)=0](https://tex.z-dn.net/?f=%282x-7%29%28x%2B2%29%3D0)
. Set each factor equal to 0 and solve. 2x-7=0 gives you x=7/2 & x+2=0 gives you x=-2. Since we're working with lengths and widths, the answer cannot be negative. Therefore, your width equals 7/2. To find the length, substitute 7/2 into the original expression for length (2x-3). That gives you 2*(7/2)-3=7-3=4. The length is 4.
Answer:
neither
![a_{n} = \frac{n+1}{n+4}](https://tex.z-dn.net/?f=a_%7Bn%7D%20%3D%20%5Cfrac%7Bn%2B1%7D%7Bn%2B4%7D)
Step-by-step explanation:
When you are rounding to a whole number, you look at the first number after the decimal point. If the number after the decimal point is 4 and under, then you keep the number in front. If the number after the decimal is 5 and above, then you round the number in front up by 1.
3.32, .32 is less than 5, therefore you keep the same number in front.
3.32 rounded to the nearest whole number would be 3.
Hope this helps!