Answer:
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.
This means that 
80% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
(35 x 3) + (55 x 2)
105 + 102
answer = 207 minutes
Answer:
3 + 5i
Step-by-step explanation:
Given
- 2i + (9 - 3i) - (6 - 10i) ← distribute parenthesis
= - 2i + 9 - 3i - 6 + 10i ← collect like terms
= 3 + 5i
Answer:
y + 6 = -5(x-1) slope-point form
y = -5x - 1 slope-intercept form
Step-by-step explanation:
We can write an equation in slope -point form
y - y1 = m(x - x1)
y - (-6) = -5(x - 1)
y + 6 = -5(x-1) slope-point form
We can rewrite it in slope-intercept form
y + 6 = - 5(x - 1)
y + 6 = - 5x + 5
y = -5x - 1 slope-intercept form