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BARSIC [14]
2 years ago
10

Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]

Mathematics
1 answer:
Jobisdone [24]2 years ago
6 0

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

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Step-by-step explanation:


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Step-by-step explanation:

the probability of making one shot is 75% or 0.75 or 3/4.

the probability to make 2 shots is then

3/4 × 3/4 = 9/16 = 0.5625

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the probability to miss 1 shot is then 25% or 0.25 or 1/4.

the probability to make at least 4 out of 5 shots is the sum of the probability to make all 5 shots plus the probability to make 4 shots.

or the probability to miss 0 plus the probability to miss 1 shot.

anyway, we can go with the positive approach. it seems to be the same complexity as the negative approach.

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the probability to e.g make the first 4 shots and miss the 5th is

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how many possibilities do we have to make 4 out of 5 shots ?

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to control,

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1/1024

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(270+90+15+1)/1024 = 376/1024

plus the 648/1024 = 1024/1024 = 1

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