Answer:
210.65 ft
round as needed
Step-by-step explanation:
Law of Cosines
c^2 = a^2 + b^2 - 2abCosC
c^2 = 125^2 + 210^2 - 2(125)(210)Cos73
c^2 = 15,625 + 44,100 - 15349.5
c^2 = 44,375.5
c = 210.654931107724132
Answer:
3 tee shirts and 2 dresshirts
Step-by-step explanation:
Answer:
d=7
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let the number of free throws = x
And the number of regular field goals = y
Total shots made by the team = 31
Equation for the shots will be,
x + y = 31 ------(1)
If the team gets 1 point for free throws and 2 points for a regular field goal,
x + 2y = 49 --------(2)
[total points gained by the team = 49]
1). Option (2) is the correct option.
2). Subtracting equation (1) from equation (2),
(x + 2y) - (x + y) = 49 - 31
y = 18
Therefore, number of regular field goals made by the team = 18
Answer:
It is not possible
Step-by-step explanation:
First 6 people have 9 friends and since 6 people can have totally the same friends which could all be each other, we would have 5 friends(from same 6 people) + 4 friends(not from the 6). Therefore we would have total 9 people/students
In second group of 8 people, their friends could entirely be the same be the same as the first group's friends or they could all be each other's friend hence just an additional 8 students to the population
In the third group of 11 people/students, same thing could apply as above but total number of students would always surpass 25 with the additional population. Example 9+8+11= 28
Therefore it is not possible that 25 students would each have those number of friends.