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docker41 [41]
2 years ago
14

There are 3 pieces of glass that are cracked. if a rock is thrown by a lawn mower hits the window, what is the probability, that

the rock hits a piece of glass that is cracked?
Mathematics
1 answer:
kirza4 [7]2 years ago
4 0

The chance or chance that the lawn mower will hit a chunk of glass that is already cracked is calculated with the aid of dividing the variety of glasses that are cracked by way of the full quantity of glasses. on this item, the unknown may be calculated through . The solution is, therefore,  0.20.

Opportunity is a measure of the chance of an event to arise. Many occasions cannot be predicted with overall reality. We are able to are expecting only the danger of an event to arise i.e. how likely they're to manifest, using it.

The possibility is the branch of arithmetic regarding numerical descriptions of how in all likelihood an occasion is to arise, or how possibly it's miles that a proposition is actual. The possibility of an occasion various between 0 and 1, where, roughly talking, 0 indicates the impossibility of the event and 1 shows reality.

The probability of an event can be calculated by possibility components via surely dividing the favorable range of effects through the full range of possible outcomes.

Learn more about the probability here brainly.com/question/24756209

#SPJ4

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I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu
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The imaginary unit i belongs to the set of complex numbers, denoted by \mathbb C. These numbers take the form a+bi, where a,b are any real numbers.

The set of real numbers, \mathbb R, is a subset of \mathbb C, where each number in \mathbb R can be obtained by taking b=0 and letting a be any real number.

But any number in \mathbb C with non-zero imaginary part is not a real number. This includes i.

  • "is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because 2=2+0i.

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising i to the i-th power. Since i=e^{i\pi/2}, we have

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D

Step-by-step explanation:

You can infer to the solution of this problem by looking at the choices. Hope this helped :)

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