1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Savatey [412]
2 years ago
11

Someone pls help fast

Chemistry
1 answer:
Zinaida [17]2 years ago
8 0

0.592 grams of O₂ gas are needed.

<h3>What is Ideal Gas ? </h3>

An ideal gas is a gas that obeys gas laws at all temperature and pressure conditions. It have velocity and mass but do not have volume. Ideal gas is also called perfect gas.

Ideal gas law equation is expressed as:

PV = nRT

where,

P = Pressure

V = Volume (in Liters)

n = Number of moles of gas

R = Ideal gas constant

T = Temperature

Here,

P = 0.505 atm

V = 869 ml = 0.869 L

R = 0.0821 L atm/K mol  [Ideal gas constant]

T = 287 K

Now put the values in above equation

PV = nRT

0.505 atm × 0.869 L = n ×  0.0821 L atm/K mol × 287 K

0.438 atm L = n × 23.56 L atm / mol

n = \frac{0.438\ \text{atm L}}{23.56\ \text{L atm / mol}}

n = 0.0185 mol

Now,

Mass of oxygen = Number of moles × Molar Mass

                           = 0.0185 mol × 32 g/mol

                           = 0.592 gram

Thus from the above conclusion we can say that 0.592 grams of O₂ gas are needed.

Learn more about the Ideal Gas here: brainly.com/question/20348074
#SPJ1

You might be interested in
What is the mass of 2.50 moles of NaCl
garik1379 [7]

Answer:

The mass of 2,50 moles of NaCl is 146, 25 g.

Explanation:

First we calculate the mass of 1 mol of NaCl, starting from the atomic weights of Na and Cl obtained from the periodic table. Then we calculate the mass of 2.50 moles of compound, making a simple rule of three:

Weight NaCl= Weight Na + Weight Cl=  23 g+ 35,5 g= 58, 5 g/ mol

1 mol ------ 58, 5 g

2,5 mol---x= (2,5 mol x 58, 5 g)/ 1 mol = <u>146, 25 g</u>

8 0
3 years ago
Static charges can be applied to neutral objects by friction, induction or conduction. What do all of these methods utilize to c
MatroZZZ [7]
Electrons are valence and free moving so they take place in charge transfer
5 0
3 years ago
Which statement about electrolytic cells is correct?
ikadub [295]
The best answer choices can be A.because it reduction he eletrolytic from positive
5 0
3 years ago
what is the molecular formula for a compound with the empirical formula: K2SO4 and a molecular mass of 696g​
LekaFEV [45]

Answer:

K8S4O16 or K8(SO4)4 depending on if the SO4 is supposed to represent sulfate or not

Explanation:

Find the molar mass of K2SO4 first:

2K + S + 4O ≈ 174 g/mol

Divide the goal molar mass of 696 by the molar mass of the empirical formula:

696 / 174 = 4

This means you need to multiply everything in the empirical formula by 4:

K2SO4 --> K8S4O16 or K8(SO4)4 depending on if the SO4 is for sulfate or not

4 0
3 years ago
Is anybody good in Chemistry that can help me with this?​
sesenic [268]

Answer:

just replace the 9 mole with 3.68 g of Al .

I think it will help you.

5 0
3 years ago
Other questions:
  • A(n)<br> wave carries energy through matter.
    15·1 answer
  • What is the total number of orbitals found in the second energy level? openstudy?
    12·2 answers
  • What do dipole-dipole forces do?
    15·2 answers
  • Write balanced complete ionic equation for the reaction cas(aq)+cucl2(aq)→cus(s)+cacl2(aq)
    15·2 answers
  • How does the carbon chain length affect the polarity of an alcohol? What effect does this have on the solubility of the alcohol
    5·1 answer
  • Certain types of organisms such as fireflies and anglerfish can produce light
    11·2 answers
  • . What percentage of the electricity in the United States is generated directly from solar energy?
    8·1 answer
  • Given the reaction:
    14·1 answer
  • 1. Chlorobenzene, C6H5C1, is used in the production of chemicals such as aspirin
    12·1 answer
  • Phosphorus pentachloride decomposes according to the chemical equation
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!