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3 years ago

When 1mol of a gas burns at constant pressure, it produces 2430 j of heat and does 5 kj of work?

1 answer:

7 0

Convert 2430j to Kj that is divide by 1000
2430/1000=2.430
delta E =Q+W
q is the heat done
w is the work done and since is work is done is by the system therefore it is negative
w is therefore -5kj
q=-2.430
delta E =-2.430 + -5= -7.43kj/mol

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3 years ago

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3 years ago

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Answer:

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3 years ago

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Rainbow [258]

Answer: P₂=0.44 atm

Explanation:

For this problem, we are dealing with temperature and pressure. We will need to use Gay-Lussac's Law.

Gay-Lussac's Law: $\frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }$

First, let's do some conversions. Anytime we deal with the Ideal Gas Law and the different laws, we need to make sure our temperature is in Kelvins. Since T₂ is 64°C, we must change it to K.

64+273K=337K

Now, it may be uncomfortable to use kPa instead of atm, so let's convert kPa to atm.

$56.0kPa*\frac{1000Pa}{1kPa} *\frac{atm}{101325Pa} =0.55atm$

Since our units are in atm and K, we can use Gay-Lussac's Law to find P₂.

$P_{2} =\frac{T_{2} P_{1} }{T_{1} }$

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4 years ago