Question

How many moles are in 3.45 g of Ba(CIO3)2 ?

Answer 1

Answer:

0.0113 mol Ba(ClO₃)₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structures

• Reading a Periodic Table
• Using Dimensional Analysis

Explanation:

Step 1: Define

3.45 g Ba(ClO₃)₂

Step 2: Identify Conversions

Molar Mass of Ba - 137.33 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Ba(ClO₃)₂ - 137.33 + 2(35.45) + 6(16.00) = 304.33 g/mol

Step 3: Convert

1. Set up:                              $\displaystyle 3.45 \ g \ Ba(ClO_3)_2(\frac{1 \ mol \ Ba(ClO_3)_2}{304.33 \ g \ Ba(ClO_3)_2})$
2. Multiply/Divide:                $\displaystyle 0.011336 \ mol \ Ba(ClO_3)_2$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.011336 mol Ba(ClO₃)₂ ≈ 0.0113 mol Ba(ClO₃)₂