Answer:
BX will hold 6444 in hex format.
Explanation:
From the given information:
We need to understand that AX is 64-bit hex number.
When performing ASM instruction (Assembly language instruction),
The addition of 2111 + 4333 = 6444 will be in BX.
This is because ADD, BX, AX will add bx and ax; and the final outcome will be stored in BX.
∴
BX will hold 6444 in hex format.
Answer:
oDI 5200.48 implements the DOD CUI program as required by EO 13556
Explanation:
Answer:
Following are the expression in the Java language
public class Main
{
public static void main(String[] args) // Main method
{
boolean young= true; // variable declaration
boolean famous= true;// variable declaration
if(young && famous) // check the condition
System.out.println("You must be rich " );// display message
}
}
Output:
You must be rich
Explanation:
Following are the description of the above statement
- Declared a variable "young " of the boolean type that is initialized with the "true" value.
- Declared a variable "famous " of the boolean type that is initialized with the "true" value.
- Check the condition of if() block.If the condition is true then it executed the condition inside the if block.
- Finally ,print the message "You must be rich!"
