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dimulka [17.4K]
2 years ago
12

A school cafeteria uses 10

Mathematics
1 answer:
gladu [14]2 years ago
8 0

Using proportions, it is found that there are 5 cups of milk in each bowl of chocolate pudding.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

The cafeteria used 10 quarts for 8 bowls, hence the number of quarts per bowl is:

10/8 = 1.25

Each quart has 4 cups, hence the number of cups is:

4 x 1.25 = 5 cups.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

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Answer:

Step-by-step explanation:

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3 years ago
The expression cos 42° in terms of sine
GalinKa [24]

Answer:

\because \:  \cos \theta =  \sin \: (90 \degree -  \theta) \\  \\  \therefore \:  \cos \: 42 \degree =  \sin \: (90 \degree -  42 \degree) \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = \sin \: 48 \degree \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \orange{ \boxed{ \therefore \:  \cos \: 42 \degree =\sin \: 48 \degree}}

8 0
3 years ago
The radii of Earth and Pluto are 6,371 kilometers and 1,161 kilometers, respectively. Approximately how many spheres the size of
antoniya [11.8K]
The volume of a sphere is (4/3) (pi) (radius cubed).

The volume of one sphere divided by the volume of another one is

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Divide top and bottom by (4/3) (pi) and you have     (radius-A)³ / (radius-B)³
and that's exactly the same as
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I went through all of that to show you that the ratio of the volumes of two spheres
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Earth radius = 6,371 km
Pluto radius = 1,161 km

Ratio of their radii = (6,371 km) / (1,161 km)

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Note: 
I don't like the language of the question where it asks "How many spheres...".
This seems to be asking how many solid cue balls the size of Pluto could be
packed into a shell the size of the Earth, and that's not a simple solution.
The solution I have here is simply the ratio of volumes ... how many Plutos
can fit into a hollow Earth if the Plutos are melted and poured into the shell.
That's a different question, and a lot easier than dealing with solid cue balls.
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