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sleet_krkn [62]
2 years ago
12

Kevin, a manager at FitPlus fitness club, owns a website that updates information regarding his fitness club. He created backgro

und gradients by tiling gradient images across a page or element. Now, he wishes to modify these and add gradients supported by Cascading Style Sheet (CSS). Kevin would like to apply a gradient that transitions from blue for the top portion of the page to white for the bottom portion of the page. Which function should be use? a) background: linear-gradient(blue, white) b) background:linear-gradient(bottom white, top blue): c) background:linear-gradient(white, blue): d) background:linear-gradientito top blue, to bottom white):
Computers and Technology
1 answer:
frosja888 [35]2 years ago
5 0

Answer:

Background: linear-gradient (blue, white)

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Purpose of this project is to increase your understanding of data, address, memory contents, and strings. You will be expected t
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Answer:

See explaination for the details

Explanation:

#Starting point for code/programm

main:

la $a0,newLine #Print a new line

li $v0,4

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li $v0,4

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li $v0, 8 # Service 8 = read input string

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li $a1, 9

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# process first word

li $t4,0 # Intialize the couter to 0

la $t0,sstatement # Store the statement into $t0

nstart1: la $t1,fword # Store the search word into $t1

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# of input word in the given statment

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# sstatement into $t2

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# into $t3

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move $t2,$v0 # Store the return($v0) value into $t2

move $a0,$t3 # Convert $t3 to lower, if it is upper case

jal convert2lower

move $t3,$v0 # Store the return($v0) value into $t3

bne $t2,$t3,next_char1 # If both characters are not matched current

# character in the string, go to next character

addiu $t0,$t0,1 # otherwise, increment both indexes

addiu $t1,$t1,1

j loop1 # go to starting of the loop

next_char1:

la $t5,fword

bne $t5,$t1,nstart1

la $t1,fword # Store the input word into $t1

addiu $t0,$t0,1 # Increment the index to goto next character

j loop1 # go to starting of the loop

inc_counter1:

addi $t4,$t4,1 # Increment the frequency counter by 1

la $t1,fword # Store input word into $t1

j loop1 # go to starting of the loop

print_output1:

la $t0,fword

L1:

lb $a0,($t0)

beq $a0,'\n',exL1

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move $a0,$v0

li $v0,11

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exL1:

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li $t4,0 # Intialize the couter to 0

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# of input word in the given statment

lb $t2,($t0) # Load the starting address(character) of

# sstatement into $t2

lb $t3,($t1) # Load the starting address of input word

# into $t3

beq $t3,'\n',inc_counter2

beqz $t3,inc_counter2 # If $t3 is null , exit loop and print output

beqz $t2,print_output2 # If $t2 is null , exit loop and print output

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move $t2,$v0 # Store the return($v0) value into $t2

move $a0,$t3 # Convert $t3 to lower, if it is upper case

jal convert2lower

move $t3,$v0 # Store the return($v0) value into $t3

bne $t2,$t3,next_char2 # If both characters are not matched current

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addiu $t1,$t1,1

j loop2 # go to starting of the loop

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la $t5,sword

bne $t5,$t1,nstart2

la $t1,sword # Store the input word into $t1

addiu $t0,$t0,1 # Increment the index to goto next character

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inc_counter2:

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la $t1,sword # Store input word into $t1

j loop2 # go to starting of the loop

print_output2:

la $t0,sword

L2:

lb $a0,($t0)

beq $a0,'\n',exL2

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move $a0,$v0

li $v0,11

syscall

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j L2

exL2:

la $a0,colon

li $v0,4

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move $v0,$a0

blt $a0,'a',return2

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