Question

Dave leaves his office in Padelford Hall on his way to teach in Gould Hall. Below are several different scenarios. Take distance units to be “feet” and time units to be “minutes.” Assume Dave’s path to Gould Hall is along a straight line which is 2400 feet long.
I. Dave leaves Padelford Hall and walks at a constant spend until he reaches Gould Hall 10 minutes later.
II. Dave leaves Padelford Hall and walks at a constant speed. It takes him 6 minutes to reach the halfway point. Then he gets confused and stops for 1 minute. He then continues on to Gould Hall at the same constant speed he had when he originally left Padelford Hall.
III. Dave leaves Padelford Hall and walks at a constant speed. It takes him 6 minutes to reach the half-way point. Then he gets confused and stops for 1 minute to figure out where he is. Dave then continues on to Gould Hall at twice the constant speed he had when he originally left Padelford Hall.

g. Using all three scenarios, represent each scenario as an algebraic function.

Answer 1

See below for the algebraic expressions of the scenarios.

How to represent the scenarios?

The given parameters are:

• Distance = 2400 feet
• Unit of time = Minutes

Scenario 1

Represent the speed with x.

So, we have:

Speed = Distance/Time

The time is given as:

Time = 10 minutes

Since he did not stop at all;

The speed is

x = 2400/10

Multiply both sides by 10

10x = 2400

The above expression represents the scenario 1.

Scenario 2

Represent the speed with x, and time with t

So, we have:

Speed = Distance/Time

The time to reach halfway is given as:

Time = 6 minutes

He stopped for 1 minute, before continuing at the same initial speed

So, the total time it 13 minutes

The speed is represented as:

x = 2400/13

Multiply both sides by 13

13x = 2400

The above expression represents the scenario 2.

Scenario 3

Represent the speed with x, and time with t

So, we have:

Speed = Distance/Time

The time to reach halfway is given as:

Time = 6 minutes

He stopped for 1 minute, before continuing at twice the initial speed

So, the total time is

t = 6 + 1 + 1/2 * 6 minutes

t = 10 minutes

The speed is represented as:

x = 2400/10

Multiply both sides by 10

10x = 2400

The above expression represents the scenario 3.

Read more about algebraic expressions at:

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