Answer:
P(B) = 8/12
P(R | B) = 4/11
P(B ∩ R) = 8/33
The probability that the first ball chosen is black and the second ball chosen is red is about 24 percent.
Step-by-step explanation:
I just got it right on edge 2020. Good luck with school!!
-4/8 i think that is right not sure tho so you might wanna wait for ohter answer
Answer:

Step-by-step explanation:
