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Tamiku [17]
2 years ago
6

Please Help me with this problem!!! ASAP

Mathematics
1 answer:
castortr0y [4]2 years ago
6 0

The average rate of change is -5 per month

<h3>How to determine the average rate of change?</h3>

The interval is given as:

July to December

From the graph, we have:

July = 110

December = 30

The average rate of a function over the interval (a, b) is calculated as:

Rate = [f(b) - f(a)]/[b - a]

So, we have:

Rate = (30 - 110)/(December- July)

This gives

Rate = (30 - 110)/(12 - 7)

Evaluate

Rate = -16

Hence, the average rate of change is -5 per month

Read more about average rate of change at:

brainly.com/question/23715190

#SPJ1

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36 first-graders and 14 other students attended a school assembly. What percentage of the students at the assembly were first-gr
dimaraw [331]

Answer: 18%

Step-by-step explanation: Add 36 + 14 = 50

Then 36*50/100=18

5 0
2 years ago
A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove
Anna11 [10]

<u>Answer:</u>

The amount lost over the 3 years s 2567.25£  

<u>Explanation:</u>

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

= $18000 \times\left(\frac{95}{100}\right)^{3}$

 = 15432.75£ which is the value of the car after 3 years

Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.  

6 0
3 years ago
10x4ones= ones=<br> 10x2tens= tens=
Vsevolod [243]
Well, 10x4=40 because 10+10+10+10=40 and that means your answer must be 40 ones or you asked something else.
5 0
3 years ago
Answer it right and i'll try to give you brainliest.
mario62 [17]

Answer:

384 cm²

Step-by-step explanation:

Since it is a square pyramid, the total surface area of the pyramid is the area of its square base plus the area of its 4 triangular faces.

\boxed{area \: of \: triangle =  \frac{1}{2} \times base \times height }

Area of a triangular face

= ½ ×12 ×10

= 60 cm²

\boxed{area \: of \: square = side \times side}

Base area of pyramid

= 12 ×12

= 144 cm²

∴ Surface area of pyramid

= 4(60) +144

= 240 +144

= 384 cm²

7 0
3 years ago
I need help please list all the available factors. PLEASE
lara [203]
Thing I no this one I just forgot
3 0
3 years ago
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