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lubasha [3.4K]
2 years ago
15

If 2y=x³ + 2x², find dy/dx when x=2.

Mathematics
1 answer:
scZoUnD [109]2 years ago
5 0

Answer:

10

Step-by-step explanation:

\boxed{\textsf{If }y=x^n,\: \textsf{then }\dfrac{\text{d}y}{\text{d}x}=nx^{n-1}}

<u>Given equation</u>:

2y=x^3+2x^2

Isolate y by dividing both sides by 2:

\implies y=\dfrac{1}{2}x^3+x^2

Differentiate with respect to x:

\implies \dfrac{\text{d}y}{\text{d}x}=3 \cdot \dfrac{1}{2}x^{3-1}+2 \cdot x^{2-1}

\implies \dfrac{\text{d}y}{\text{d}x}=\dfrac{3}{2}x^2+2x

Finally, substitute x = 2 into the differentiated equation:

\begin{aligned} \implies \dfrac{\text{d}y}{\text{d}x} & =\dfrac{3}{2}(2)^2+2(2)\\\\ & = \dfrac{3}{2}(4)+4\\\\ & = \dfrac{12}{2}+4\\\\ & = 6+4\\\\ & = 10\end{aligned}

Learn more about differentiation here:

brainly.com/question/27958412

brainly.com/question/26488862

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Answer:

\sqrt {72} = 6\sqrt 2

Step-by-step explanation:

Ashton estimates the square root of 72 in the following way:

√72=

2√36=

2×6=12

a) Explain why his reasoning is incorrect

This is incorrect because \sqrt2 * 6 is the correct answer but he has missed the square root term on 2.

=\sqrt {2^2X2X3^2 }

=\sqrt {2^2} \sqrt 2 \sqrt {3^2 }

=2 X \sqrt 2 X 3

= \sqrt 2 X 6

or can be written as:

= 6\sqrt 2

b) Estimate the square root of 72 to the nearest tenth without using your calculator. Show your work.

Find the factors of 72 we get \sqrt {2X2X2X3X3 }  

Now, we will combine 2 terms if the are same so,

=\sqrt {2^2X2X3^2 }

=\sqrt {2^2} \sqrt 2 \sqrt {3^2 }

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4 0
3 years ago
Explain how you could convert 3/4 ton to ounces
krek1111 [17]
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8 0
4 years ago
Use the given data to find the 95% confidence interval estimate of the population mean μ. Assume that the population has a norma
loris [4]

Answer: For 95% Confidence Interval:

Upper Limit = 110.2

Lower Limit = 97.8

95% Confidence Interval = [97.8, 110.2]

Step-by-step explanation:

Given that,

Mean(M) = 104

Standard Deviation(SD) = 10

Sample Size(n) = 10

Formula for calculating 95% Confidence Interval are as follows:

Standard error(SE) =\frac{SD}{\sqrt{n} }

                         = \frac{10}{\sqrt{10} }

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⇒ M ± Z_{0.95} × SE

= 104 ± (1.96)(3.164)

= 104 ± 6.20

∴ Upper Limit = 104 + 6.20 = 110.2

   Lower Limit = 104 - 6.20 = 97.8

So,

95% Confidence Interval = [97.8, 110.2]

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3 years ago
Which measurement is greater 0.087 kg or 0.800 kg
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Answer:

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Step-by-step explanation:

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