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stira [4]
3 years ago
11

At a track meet Sammy finished the race in 25.98 seconds. Tom finished the 100 meter race in 12.54 seconds. Which runner ran the

faster average
Mathematics
1 answer:
Basile [38]3 years ago
5 0

Answer: Sammy


Step-by-step explanation: If Tom finished the 100 meter race in 12.54 seconds that means he would have been going at an average of 7.97 seconds and if Sammy is finishing a 100 meter race in 25.98 seconds he would have been going at an average of 3.84. Therefore Sammy is going at a faster average.


Hope this helps!


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A, b, c, and d please
DIA [1.3K]
<h2>Answers / Step-by-step explanation:</h2><h3>a. What is the length of one side of the square.</h3>

<em>Looking at the image, the radius (r) of the circle appears to cover half of the length of a side of the square. Hence, the side of the square has a length of </em><em>2r</em><em>.</em>

<em />

<u><em>-------------------------------------------------------------------------------------------------------</em></u>

<em />

<h3>b. The formula A= πr² is used to find the area of a circle. The formula A=4r² can be used to find the area of the square. Write the ratio of the area of the circle to the area of the square in the simplest form.</h3>

<em />Ratio=\frac{\pi r^{2} }{4r^2} =\frac{\pi}{4}.

<em>Notice that the value "r²" disappears from the expression because is being multiplied and divided by it at the same time.</em>

<em />

Ratio=\frac{4\pi }{16} =0.7854.

<em />

<u><em>-------------------------------------------------------------------------------------------------------</em></u>

<em />

c. Complete the table.

<em>To complete each cell of the table, simply take the equation of the asked parameter and substitute the value of r by the number indicated in the title of the column. For example, column 3 should be filled out like this:</em>

Area of Circle (units²): π(3)²or 9π.

Length of 1 Side of the Square: 2r= 2(3)= 6.

Area of Square (units²)= 4r²= 4(3)²= 36.

Ratio: \frac{\pi}{4}.

<em>Do the same for all the other columns. </em>

<em>The answers to the table are presented on the attached image</em><em>.</em>

<em />

<u><em>-------------------------------------------------------------------------------------------------------</em></u>

<em />

d. What can you conclude about the relationship between the area of the circle and the square?

<em>They will always have the same value, π/4, regardless of the size of the square and circle. As long as the circle borders meet the square's at the middle of each side of the square, the relationship will be the same</em><em>.</em>

4 0
2 years ago
I want to know if mammals usually have more
DENIUS [597]

The graph that would allow the comparison between the median number of teeth for mammals and reptiles easily is a Box Plot.

<h3>Median</h3>

The median of a set of data is the midpoint of values in a data set. It shows the value that divides the data set into two halves.

<h3>Box plot</h3>
  • A box plot is a type of graph used in data analysis to visualize the distribution of numerical data and skewness by displaying the data quartiles and averages.

Box plots are also known as box and whisker plot.

  • Box plots are used to compare visually differences among different samples or groups such medians, ranges, and outliers.

Therefore, the graph that would allow the comparison between the median number of teeth for mammals and reptiles easily is a Box Plot.

Learn more about Box plots and median at: brainly.com/question/16796572

8 0
2 years ago
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Answer:

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Solve for  w  by cross multiplying.

6 0
3 years ago
Read 2 more answers
xand y are light house. y being 20km due east of x and from a ship due south of x the bearing of y was 055°. what is the distanc
leonid [27]

Answer:

I) |xz| ≈ 28.6 km

II) |yz| ≈ 34.8 km

Step-by-step explanation:

Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)

|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°

Using Trigonometric ratio - SOHCAHTOA

I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20

|xz| = 20 * Tan 55 = 20 * 1.428

|xz| = 28.56 km

|xz| ≈ <u>28.6 km</u>

<u />

II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|

|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°

|yz| = 20 ÷ 0.574 = 34.84 km

|yz| ≈ <u>34.8 km</u>

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svp [43]
The answer is ( 23,7)
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