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KatRina [158]
2 years ago
6

The sum of a number increased by three and the number decreased by seven

Mathematics
1 answer:
mash [69]2 years ago
8 0

Answer is (n + 3) + (n - 7)

Simplified to 2n - 4

Using “n” for number

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Complete the net worth statement. What is the net worth of the individual?
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Answer:

hard question you got there

Step-by-step explanation:

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2 years ago
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Help me pls! I have to get his done.<br>Factorise this!<br>2x^2+5x+3​
MArishka [77]

Hello there!☺

Answer:\boxed{(2x+3)(x+1)}

Explanation:

2x^2+5x+3 Factorized

To factor 2x^2+5x+3, we will have to do it by grouping.

2x^2+5x+3\\(2x+3)(x+1)

(2x+3)(x+1) is your answer.

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8 0
3 years ago
Can we obtain a diagonal matrix by multiplying two non-diagonal matrices? give an example
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Yes, we can obtain a diagonal matrix by multiplying two non diagonal matrix.

Consider the matrix multiplication below

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]   \left[\begin{array}{cc}e&f\\g&h\end{array}\right] =  \left[\begin{array}{cc}a e+b g&a f+b h\\c e+d g&c f+d h\end{array}\right]

For the product to be a diagonal matrix,

a f + b h = 0 ⇒ a f = -b h
and c e + d g = 0 ⇒ c e = -d g

Consider the following sets of values

a=1, \ \ b=2, \ \ c=3, \ \ d = 4, \ \ e=\frac{1}{3}, \ \ f=-1, \ \ g=-\frac{1}{4}, \ \ h=\frac{1}{2}

The the matrix product becomes:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}\frac{1}{3}&-1\\-\frac{1}{4}&\frac{1}{2}\end{array}\right] = \left[\begin{array}{cc}\frac{1}{3}-\frac{1}{2}&-1+1\\1-1&-3+2\end{array}\right]= \left[\begin{array}{cc}-\frac{1}{6}&0\\0&-1\end{array}\right]

Thus, as can be seen we can obtain a diagonal matrix that is a product of non diagonal matrices.
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3 years ago
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maks197457 [2]
16/21 is your answer

You can take a 2 out of both numbers to get your answer

I hope this helped! :)

3 0
3 years ago
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vagabundo [1.1K]
I'm not sure if this is correct but you would put it into an equation while you solve for X. so 0.75x=150  or equivalently would be like  (3/4)x=150 Then after that you would divide both sides by 0.75 or 3/4 
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