Factorise a x + b x minus A Y minus b y

Two random samples are taken, with each group asked if they support a particular candidate. A summary of the sample sizes and pr

Minchanka [31]

Answer:

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98[/tex[ or 98%Step-by-step explanation:A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval". The margin of error is the range of values below and above the sample statistic in a confidence interval. Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean". [tex]p_1$ represent the real population proportion for 1

$\hat p_1 =0.768$ represent the estimated proportion for 1

$n_1=92$ is the sample size required for 1

$p_2$ represent the real population proportion for 2

$\hat p_2 =0.646$ represent the estimated proportion for 2

$n_2=95$ is the sample size required for 2

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

For this case we have the confidence interval given by: (-0.0313,0.2753). From this we can find the margin of erro on this way:

$ME= \frac{0.2753-(-0.0313)}{2}=0.1533$

And we know that the margin of erro is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

We have all the values except the value for $z_{\alpha/2}$

So we can find it like this:

$0.1533=z_{\alpha/2} \sqrt{\frac{0.768(1-0.768)}{92} +\frac{0.646 (1-0.646)}{95}}$

And solving for $z_{\alpha/2}$ we got:

$z_{\alpha/2}=2.326$

And we can find the value for $\alpha/2$ with the following excel code:

"=1-NORM.DIST(2.326,0,1,TRUE)"

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98$ or 98%

7 0

3 years ago

A mouse is traveling at a rate of 100 feet per hour. One half hour later, a snake smells the

Arlecino [84]

Let, snake catches the mouse in t hours. Till then mouse is travelling from

( t + 1.5 ) hours.

Distance, travelled by mouse in t hours is, $d = 100(t+ 1.5)$ .

To catch the mouse snake had to travel the same distance d in t hours.

So,

$200t = 100( t + 1.5 )\\\\2t = t + 1.5\\\\t = 1.5 \ hours$

Therefore, snake will catch mouse in 1.5 hours.

5 0

3 years ago

If x=6 find the value of x/2

nekit [7.7K]

Answer:

3

Step-by-step explanation:

6/2=3

7 0

3 years ago

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What’s the surface area in square centimeters???

choli [55]

Answer: 1029

Step-by-step explanation:

3 0

3 years ago

Can y’all help with these to answer?

Soloha48 [4]

Answer:

1) 9:14

2)4:1

Step-by-step explanation:

You have to have all of the teachers compared to all of the adults (teachers included)

You have to simplify 12:3 and you get 4:1.

3 0

3 years ago

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Factorise a x + b x minus A Y minus b y​

Factorise a x + b x minus A Y minus b y