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Sergio039 [100]
2 years ago
5

10 Points please help with my calculus HW

Mathematics
1 answer:
Zepler [3.9K]2 years ago
6 0

The values based on the calculus computed will be 10✓5, 10✓1, and 20.

<h3>How to calculate the value?</h3>

dy/dt = 5 units.

Differentiate with respect to t.

dx/dt = 1/2✓x dx/dt

dyldt = 5.

dx/dt = 2✓x × 5 = 10✓x

a. When x = 1/5

dx/dt = 10 × ✓1/5 = 10✓5

b. x = 1

Differentiate it

dx/dt = 10✓1

c. x = 4

dx/dt = 10✓4 = 20

Learn more about <em>calculus</em> on:

brainly.com/question/24430269

#SPJ1

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Mars2501 [29]

Answer:

  • <u><em>Rounding to nearest tenth of centimeter, the ball bounces 192.1 cm high on the 5th bounce.</em></u>

<u><em></em></u>

Explanation:

The <em>ball is dropped from a height of 900 centimeters</em>.

Since the heights form a <em>geometric sequence,</em> you can find a common ratio between consecutive terms. This is:

  • Height bounce 2 / height bounce 1 = 560 / 800 = 0.7
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Hence, the ratio of the geometric sequence is 0.7, and taking bounce 1 as the start of the sequence, the general term of the sequence is:

            a_n=800(0.7)^{n-1}

With that formula you can find any term:

             n=1,a_1=800(0.7)^{(1-1)}=800(0.7)^0=800\\ \\ n=2,a_{2}=800(0.7)^{(2-1)}=800(0.7)=560\\ \\n=5,a_{5}=800(0.7)^{(5-1)}=800(0.4)^4=192.08

Rounding to <em>nearest tenth of centimeter</em>, the ball bounces 192.1 cm high on the 5th bounce.

4 0
4 years ago
What is the value of the expression (-2t^2)^3' when 't = -3'?
aleksandrvk [35]

Answer:

I believe it is 46656

Step-by-step explanation:

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3 years ago
Help me: Solve: z^4 = -4
Bogdan [553]

<u>z²-2i=0</u>

Answer:

Solution given:

z⁴=-4

doing square root on both side

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we know i²=-1

substituting i² we get

z²=\sqrt{2²*i²}

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z²-2i=0 is a required answer. where

z² and 2 is real number.

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Answer:

Step-by-step explanation:

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