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elena55 [62]
4 years ago
9

Of 900 centimeters. The table shows the height of each bounce.

Mathematics
1 answer:
Mars2501 [29]4 years ago
4 0

Answer:

  • <u><em>Rounding to nearest tenth of centimeter, the ball bounces 192.1 cm high on the 5th bounce.</em></u>

<u><em></em></u>

Explanation:

The <em>ball is dropped from a height of 900 centimeters</em>.

Since the heights form a <em>geometric sequence,</em> you can find a common ratio between consecutive terms. This is:

  • Height bounce 2 / height bounce 1 = 560 / 800 = 0.7
  • Height bound 3 / height bounce 2 = 392 / 560 = 0.7

Hence, the ratio of the geometric sequence is 0.7, and taking bounce 1 as the start of the sequence, the general term of the sequence is:

            a_n=800(0.7)^{n-1}

With that formula you can find any term:

             n=1,a_1=800(0.7)^{(1-1)}=800(0.7)^0=800\\ \\ n=2,a_{2}=800(0.7)^{(2-1)}=800(0.7)=560\\ \\n=5,a_{5}=800(0.7)^{(5-1)}=800(0.4)^4=192.08

Rounding to <em>nearest tenth of centimeter</em>, the ball bounces 192.1 cm high on the 5th bounce.

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