Answer:
Circular paraboloid
Step-by-step explanation:
Given ,
Here, these are the respective 
axes components.
- <em>Component along x axis
</em>
- <em>Component along y axis
</em>
- <em>Component along z axis
</em>
We see that , from the parameterised equation , 
This can also be written as :
This is similar to an equation of a parabola in 1 Dimension.
By fixing the value of z=0,
<u><em>We get 
which is equation of a parabola curving towards the positive infinity of y-axis and in the x-y plane.</em></u>
By fixing the value of x=0,
<u><em>We get 
which is equation of a parabola curving towards positive infinity of y-axis and in the y-z plane. </em></u>
Thus by fixing the values of x and z alternatively , we get a <u>CIRCULAR PARABOLOID. </u>
Answer:
The answer should be .25
Step-by-step explanation:
The answer should be .25 because:
- there are 4 places you can score and since you want it to land on 5 and there is only one 5 it counts as a 1
- the since there are 4 in total and you want to land on 1 you get 1/4 the number one standing for there only being one 5 and the 4 standing for the number of places to land on.
-then you convert the 1/4 into a decimal which makes .25
The answer to (-5)-3 is -8. I may be wrong but I did the work.
Answer:
a=4
c=5
e=7
f=1
Step-by-step explanation:
the simplest method would be to start with a(2)"squared" (being '4' as this will get you closest to 15. So 16 -1 (being 'c') = 15. now plug those into the other equations and work the other numbers out.
No need to fear, thehotdogman93 is here!
The first step is to get rid of those very large numbers. It's going to be very difficult to factor unless we can bring those high numbers down. So lets see if we can factor each term.
So after dividing 49 with every single digit. The only number that divides evenly is 7 and one, and 16 isnt divisible evenly by 7 so that didn't work. Looks like we're gonna have to work with these big numbers.
There is something interesting though about these numbers. 16 and 49 are both perfect squares. 16 is the same as 4^2 and 49 is the same as 7^2. So we can factor the whole trinomial as:
If we were to expand this out as:
and multiply it back into the original form. It would match with the expression we started with. The 4's would multiply back into 16x^2 and the 7's would multiply back into 49.
Additionally 4 * -7 is -28, so you can combine two -28x's into the -56x term in the original trinomial.
Thus, the answer is yes you can, and the answer is:
