Question

Three strings, attached to the sides of a rectangular frame, are tied together by a knot as shown in the figure. The magnitude of the tension in the string labeled C is 56.3 N.
Calculate the magnitude of the tension in the string marked A.

Answer 1

The magnitude of the tension in the string marked A and B is mathematically given as

A = 52.5 N

What is the magnitude of the tension in the string marked A?

Generally, the equation for is mathematically given as

tan=3/8

negative x

$B= tan\phi \\tan \phi=5/4$

negative x

C= tan=1/6

Hence, considering the Horizontal components

74.9cos(9.46) = A*cos(20.6) + B*cos(51.3)

A = 78.9 - 0.668B

Vertical components

74.9*sin(9.46) + Asin(20.6) = Bsin(51.3)

40.07 = 1.015B

B = 39.5 N

In conclusion, Sub the value of B is the equation of A

A = 78.9 - 0.668B

Sub

A = 78.9 - 0.668( 39.5 N)

A = 52.5 N

Read more about tension

brainly.com/question/15880959

#SPJ1