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dimulka [17.4K]
1 year ago
10

A car travelling at 5.0 m/s starts to speed up. After 3.0 s its velocity has increased to 11 m/s. a) What is its acceleration? (

Assume it to be uniform.) b) What distance does it travel while speeding up?​
Physics
1 answer:
lions [1.4K]1 year ago
4 0

initially, the car is traveling at 5.0 m/s.

so, we know acceleration for changing velocity is :

a = (v-v_{o})/t ..........(i)

where v is the final velocity

v_{o} is the initial velocity

t is the time taken to change velocity

Now, as per the question :

initial velocity, v_{o}=5.0 m/s

final velocity, v =11 m/s

time taken, t = 3 s

putting the values in equation (i),

a = ( 11-5 )/3

a = 2 m/s²

Therefore, a, after 3 s, is  <em>2 m/s².</em>

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castortr0y [4]

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Collect like terms

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-1.55C = 32

Divide both sides by -1.55

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C = -20.65

Recall that: F = ¼C

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F = -5.1625

5 0
3 years ago
MY LAST ONE&lt;,Brainliest for best answer!
grigory [225]
_Award brainliest if helped!
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Convert the following:
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