Question

What is the index of refraction of the second medium if a ray that makes an angle 45.0° in Flint Glass (n=1.65) makes an angle of 41.3° in the new medium?1.801.771.541.51

Answer 1

ANSWER:

2nd option: 1.77

STEP-BY-STEP EXPLANATION:

Given:

Angle medium 1 = 45°

Angle medium 2 = 41.3°

n medium 1 = 1.65

We can determine the index of refraction of the second medium using the following formula:

$\begin{gathered} n_1\cdot\sin\theta_1=n_2\cdot\sin\theta_2 \\ \\ \text{ We replacing} \\ \\ \:1.65\cdot\sin45\degree=n_2\cdot\sin41.3°\:\: \\ \\ n_2=\frac{1.65\cdot\sin45\degree}{\sin41.3\degree} \\ \\ n_2=1.77 \end{gathered}$

The index of refraction the new medium is equal to 1.77

Therefore, the correct answer is 2nd option: 1.77