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Mrrafil [7]
1 year ago
12

What is the index of refraction of the second medium if a ray that makes an angle 45.0° in Flint Glass (n=1.65) makes an angle o

f 41.3° in the new medium?1.801.771.541.51
Physics
1 answer:
Aleonysh [2.5K]1 year ago
6 0

ANSWER:

2nd option: 1.77

STEP-BY-STEP EXPLANATION:

Given:

Angle medium 1 = 45°

Angle medium 2 = 41.3°

n medium 1 = 1.65

We can determine the index of refraction of the second medium using the following formula:

\begin{gathered} n_1\cdot\sin\theta_1=n_2\cdot\sin\theta_2 \\  \\ \text{ We replacing} \\  \\ \:1.65\cdot\sin45\degree=n_2\cdot\sin41.3°\:\: \\  \\ n_2=\frac{1.65\cdot\sin45\degree}{\sin41.3\degree} \\  \\ n_2=1.77 \end{gathered}

The index of refraction the new medium is equal to 1.77

Therefore, the correct answer is 2nd option: 1.77

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Question:
exis [7]

Answer:

She can swing 1.0 m high.

Explanation:

Hi there!

The mechanical energy of Jane (ME) can be calculated by adding her gravitational potential (PE) plus her kinetic energy (KE).

The kinetic energy is calculated as follows:

KE = 1/2 · m · v²

And the potential energy:

PE = m · g · h

Where:

m = mass of Jane.

v = velocity.

g = acceleration due to gravity (9.8 m/s²).

h = height.

Then:

ME = KE + PE

Initially, Jane is running on the surface on which we assume that the gravitational potential energy of Jane is zero (the height is zero). Then:

ME = KE + PE      (PE = 0)

ME = KE

ME = 1/2 · m · (4.5 m/s)²

ME = m · 10.125 m²/s²

When Jane reaches the maximum height, its velocity is zero (all the kinetic energy was converted into potential energy). Then, the mechanical energy will be:

ME = KE + PE      (KE = 0)

ME = PE

ME = m · 9.8 m/s² · h

Then, equallizing both expressions of ME and solving for h:

m · 10.125 m²/s² =  m · 9.8 m/s² · h

10.125 m²/s² / 9.8 m/s²  = h

h = 1.0 m

She can swing 1.0 m high (if we neglect dissipative forces such as air resistance).

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3 years ago
Which term describes the quantity of energy transferred from a warmer object to a cooler object?
Mars2501 [29]

Answer: B

Explanation:

6 0
3 years ago
Why is the picture above not an accurate representation of charges and their field lines?
pochemuha
Because field lines don’t all go in to the pole. The bottom half go outwards not inwards.
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2 years ago
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A cyclotron is to accelerate protons to an energy of 5.4 MeV. The superconduction electromagnet of the cyclotron produces a 2.9T
mart [117]
<h3><u>Answer;</u></h3>

Radius = 0.0818 m

Angular velocity = 2.775 × 10^7 rad/sec

<h3><u>Explanation;</u></h3>

The mass of proton m=1.6748 × 10^-27 kg;  

Charge of electron e= 1.602 × 10^-19 C;  

kinetic energy E= 2.7 MeV

                          = 2.7 × 10^6 × 1.602 × 10^-19 J;

                          = 4.32 × 10^-13 Joules

But; K.E =0.5m*v^2,

Hence v=√(2K.E/m)

Velocity = 2.27 × 10^7 m/s

Angular velocity, ω = v/r

Therefore; V = ωr

Hence; V = √(2K.E/m) = ωr

r= √(2E/m)/w = √E*√(2*m)/(eB)

  = √E * √(2×1.6748×10^-27)/(1.602×10^-19 ×2.9)

but E =  4.32 × 10^-13 Joules

  r = 0.0818 m

Angular speed

Angular velocity, ω = v/r , where r is the radius and v is the velocity

Therefore;

Angular velocity = 2.27 × 10^7 / 0.0818 m

                            = 2.775 × 10^7 rad /sec

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3 years ago
Maaf sebelumnya ,bisa minta tolong kerjakan tugas saya? saya harus mengerjakan tugas Fisika yang lain . tolong bantu 4 nomer saj
AlladinOne [14]
Sorry cant not answer this question
8 0
3 years ago
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