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Alenkasestr [34]
3 years ago
5

in the diagram below, AB and BC are tangent to O. Which equation could be solved to find y, the measure of ADC

Mathematics
2 answers:
grin007 [14]3 years ago
8 0

Answer:

A

Step-by-step explanation:

∠ABC is formed by 2 tangents to the circle and is measured as

∠ABC = \frac{1}{2} (m  arc ADC - m arc AC ), that is

\frac{1}{2} (y - 119) = 61 → A

lions [1.4K]3 years ago
4 0

Answer:

A. \frac{1}{2}(y^{\circ}-119^{\circ})=61^{\circ}

Step-by-step explanation:

We have been given a diagram. We are asked to choose the equation that can be used to solve for y.

We know that measure formed by two intersecting tangents outside a circle is half the difference of corresponding arcs.

m\angle ABC=\frac{1}{2}(\widehat{ADC}-\widehat{AC})

61^{\circ}=\frac{1}{2}(y^{\circ}-119^{\circ})

Switch sides:

\frac{1}{2}(y^{\circ}-119^{\circ})=61^{\circ}

Therefore, option A is the correct choice.

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