Ask question

Ask question

All categories

Alenkasestr [34]

3 years ago

5

in the diagram below, AB and BC are tangent to O. Which equation could be solved to find y, the measure of ADC

2 answers:

grin007 [14]3 years ago

8 0

Answer:

A

Step-by-step explanation:

∠ABC is formed by 2 tangents to the circle and is measured as

∠ABC = $\frac{1}{2}$ (m arc ADC - m arc AC ), that is

$\frac{1}{2}$ (y - 119) = 61 → A

lions [1.4K]3 years ago

4 0

Answer:

A. $\frac{1}{2}(y^{\circ}-119^{\circ})=61^{\circ}$

Step-by-step explanation:

We have been given a diagram. We are asked to choose the equation that can be used to solve for y.

We know that measure formed by two intersecting tangents outside a circle is half the difference of corresponding arcs.

$m\angle ABC=\frac{1}{2}(\widehat{ADC}-\widehat{AC})$

$61^{\circ}=\frac{1}{2}(y^{\circ}-119^{\circ})$

Switch sides:

$\frac{1}{2}(y^{\circ}-119^{\circ})=61^{\circ}$

Therefore, option A is the correct choice.

You might be interested in

If r(X)=2-x^2 and w(X)=X-2, what is the range of (w*r)(X)

slega [8]

The given function are
r(x) = 2 - x² and w(x) = x - 2
<span>(w*r)(x) can be obtained by multiplying the both function together
</span>
So, <span>(w*r)(x) = w(x) * r(x) = (x-2)*(2-x²)</span>
<span>(w*r)(x) = x (2-x²) - 2(2-x²)</span>
= 2x - x³ - 4 + 2x²

∴ <span>(w*r)(x) = -x³ + 2x² + 2x - 4
</span>

<span>It is a polynomial function with a domain equal to R
</span>
The range of <span>(w*r)(x) can be obtained by graphing the function
</span>
To graph (w*r)(x), we need to make a table between x and (w*r)(x)

See the attached figure which represents the table and the graph of <span>(w*r)(x)
</span>

As shown in the graph the range of <span>(w*r)(x) is (-∞,∞)
</span>

8 0

3 years ago

Read 2 more answers

antoniya [11.8K]

answer= x=20

Step-by-step explanation:

We have, 35% × x = 7

or,

35

100

× x = 7

Multiplying both sides by 100 and dividing both sides by 35,

we have x = 7 ×

100

35

x = 20

If you are using a calculator, simply enter 7×100÷35, which will give you the answer.

5 0

2 years ago

Read 2 more answers

Find the value of B - A if the graph of Ax + By = 3 passes through the point (-7, 2), and is parallel to the graph x + 3y = -5.

Elena-2011 [213]

Answer:

$B - A = -6$

Step-by-step explanation:

Given

Point: (-7,2)

x + 3y = -5

Required

Find B- - A in Ax + By = 3

To start with; we need to calculate the slope of x + 3y = -5

$x + 3y = -5$

Subtract x from both sides

$x - x + 3y = -5 - x$

$3y = -5 - x$

Divide both sides by 3

$\frac{3y}{3} = -\frac{5}{3} - \frac{x}{3}$

$y = -\frac{5}{3} - \frac{x}{3}$

The slope of the line is the coefficient of x

Slope = $- \frac{1}{3}$

The question says line Ax + By = 3 is parallel to line x + 3y = -5; This means that they have the same slope of $- \frac{1}{3}$

Having calculated the slope, next is to calculate the equation of the line using the following formula;

$m = \frac{y - y_1}{x - x_1}$

Where m is the slope; m = $- \frac{1}{3}$ ; $(x_1, y_1) = (-7,2)$

Substitute these values in the formula above; the formula becomes

$-\frac{1}{3} = \frac{y - 2}{x - -7}$

$-\frac{1}{3} = \frac{y - 2}{x +7}$

Cross Multiply

$-1(x+7) = 3(y-2)$

Open brackets

$-x - 7 = 3y - 6$

Add x to both sides

$x - x - 7 = 3y - 6 + x$

$-7 = 3y - 6 +x$

Add 6 to both sides

$-7 + 6 = 3y -6 + 6 + x$

$-1 = 3y + x$

Multipby both sides by -3

$-3(-1) = -3(3y + x)$

$3 = -9y - 3x$

$-9y - 3x = 3$

$-3x - 9y = 3$

Comparing the above to Ax + By = 3

$Ax = -3x\\A = -3$

$By = -9y\\B = -9$

$B - A = -9 - (-3)$

$B - A = -9 + 3$

$B - A = -6$

3 0

3 years ago

16) Graph g(x) = x + 3 + 2

krek1111 [17]

X=1.6 just did the math

3 0

1 year ago

What is the degree of the polynomials below <br> 2x^7+4-3x^3+5x^8-4x

Nikolay [14]

The Answer should be 8

7 0

2 years ago