1) The graph
The corresponding graph shows a growing curve, its shape is kind of the right half of a parabola that opens upward and starts at the point (0, 2500).
The vertical axis corresponds to C(j), it contains divisions of 2500 units, and are marked 2500, 5000, 7500, 10000, 12500, 15000 and 17500.
The horizontal axis corresponds to j, and the marks are 75, 150, 225, 300, 375, and 450.
2) Domain
Domain is the set of possible values for the independent variable, which is placed on the horizontal axis. This is the possible values of j.
They are all the positive numbers and zero, the the domain is:
All real numbers, j, such that j ≥ 0
3) Range
Range is the set of possible images (dependent variable); this is the possible values of C(j).
As you can see on the graph C(j) ≥ 2500
Then, the range is [2500, ∞).
Out of 5 cards in the bag ...
-- There are 2 even numbers . . . 2 and 4 .
-- There are 3 odd numbers . . . 1, 3, and 5 .
So EITHER time, the probability of pulling an even number is 2/5 ,
and the probability of pulling an odd number is 3/5 .
The probability of pulling an even number the first time
AND an odd number the second time is
(2/5) x (3/5) = 6/25 = <em>24%</em> .
Answer: =2084
4+2(82)(42)+6+4+6+6+6+2+2
=4+264(42)+6+4+6+6+6+2+2
=4+2(64)(16)+6+4+6+6+6+2+2
=4+(2)(1024)+6+4+6+6+6+2+2
=4+2048+6+4+6+6+6+2+2
=2052+6+4+6+6+6+2+2
=2058+4+6+6+6+2+2
=2062+6+6+6+2+2
=2068+6+6+2+2
=2074+6+2+2
=2080+2+2
=2082+2
=2084
Answer:
32.5
Step-by-step explanation:
10 ounces is in 4 pizzas so if we want 15 pizzas we need to count up
4 can not fit into 15 so we have to stop at 12 pizzas.
Now we need to add 3 pizzas
:Note: that one pizza is 2.5 of an ounce out of 10 ounces
so after you add the 3 pizzas you have 15 but that wasnt 4 pizzas so you have 2.5 ounces left over you add those ounces to the 30 you got from the 12 ounces which you have 30 and add it to the ounces left over
2.5 + 30 = 32.5
