1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
I am Lyosha [343]
3 years ago
8

Which of the following item(s) explain the differences between the Ka values. Choose one or more: A. The oxidation state for oxy

gen in trifluoroacetate is more negative than the oxidation state for oxygen in acetate. B. The trifluoroacetate molecule has more resonance structures than the acetate molecule. C. The electron-withdrawing fluorine atoms pull electron density from the oxygen in trifluoroacetate. The negative charge is more stabilized in trifluoroacetate by this effect. D. The negative charge is on the more electronegative fluorine atom in trifluoroacetate.
Chemistry
1 answer:
Allisa [31]3 years ago
3 0

Answer:

<em>C. The electron-withdrawing fluorine atoms pull electron density from the oxygen in trifluoroacetate. The negative charge is more stabilized in trifluoroacetate by this effect.</em>

<em></em>

Explanation:

<em>The structures of trifluoroacetate and acetic acid are both shown in the image attached.</em>

<em>The trifluoroacetate anion (CF3CO2-), just like the acetate anion has in the middle, two oxygen atoms.</em>

<em>However, in the trifluoroacetate anion, there are also three electronegative fluorine atoms attached to the nearby carbon atom attached to the carbonyl, and these pull some electron density through the sigma bonding network away from the oxygen atoms, thereby spreading out the negative charge further. This effect, called the "inductive effect" stabilizes the anion formed,the trifouoroacetate anion is thus more stabilized than the acetate anion.</em>

<em>Hence, trifluoroacetic acid is a stronger acid than acetic acid, having a pKa of -0.18.</em>

<em></em>

<u><em>Hope this helps!</em></u>

<u><em>Please mark brainliest!</em></u>

You might be interested in
When cyclohexene is treated with KMnO4, H2O, the syn-1,2-diol is produced. What reaction occurs when benzene is similarly treate
Ulleksa [173]

Answer:

No reaction is observed

Explanation:

The benzene ring is aromatic. Being an aromatic ring, the benzene ring is remarkably stable to all reactions that destroy the aromatic ring.

Alkenes are oxidized to alkanols in the presence of KMnO4 but this reaction does not occur with benzene. However, substituted benzenes having hydrogen atoms attached to the substituent carbon atom can be oxidized to the corresponding carboxylic acid.

7 0
3 years ago
Which statement describes global winds?
sergejj [24]

Answer:

They blow away from poles to the equator.

Explanation:

Hello,

In this case, we must take into account that global wind systems are formed by the constant increase in the temperature of the Earth’s surface. Thus, they drive the oceans’ surface currents. In such a way, we can say wind is the basic movement of air from an area of higher pressure to an area of lower pressure, for that reason they blow away from the poles to the equator.

Best regards.

6 0
3 years ago
Read 2 more answers
Help on this question please
oee [108]

Answer:

First choice: 2

Explanation:

There are 2 phosphorous (P) in the substance.

Ignore the strontium (Sr3) part because you are looking to isolate the P from (PO4)2.

Break the chemical equation apart to get 1 Phosphorous atom, and 4 Oxygen atoms.

Now, multiple 1 by 2 because that are 2 phosphate to get 2 phosphorous atoms.

8 0
2 years ago
Sodium chloride can be produced by the reaction of sodium metal with chlorine gas. Which is the limiting reactant if 6.70 moles
Alecsey [184]

Answer:

Chlorine gas.

Explanation:

Hello!

In this case, the undergoing chemical reaction is:

2Na+Cl_2\rightarrow 2NaCl

Thus, given the moles of reacting both sodium and chlorine, we compute the moles of sodium chloride yielded by each reactant by considering the 2:2 and 1:2 mole ratios:

n_{NaCl}^{by\ Na}=6.70molNa*\frac{2molNaCl}{2molNa}=6.70molNaCl \\\\n_{NaCl}^{by\ Cl_2}=3.20molCl_2*\frac{2molNaCl}{1molCl_2}=6.40molNaCl

Thus, since chlorine yields less moles of sodium chloride, we infer it is the limiting reactant.

Best regards!

3 0
3 years ago
Given a sample of poly[ethylene-stat-(vinyl acetate)] A.Calculate the mean repeat unit molar mass for a sample of poly[ethylene-
AlladinOne [14]

Answer:

a) The mean repeat unit molar mass for PEVA is 30.72 g/mol

b) degree of polymerization of the copolymer is 1300

Explanation:

Given that;

the wt% of copolymer consist of 12.9 wt% of vinyl acetate and 87.1 wt% Ethylene.

Basis: 100 g of PEVA consist of 12.9 of vinyl acetate and 87.1g of Ethylene.

now we calculate the mole fraction of vinyl acetate Ethylene in the copolymer;

the molecular weights of vinyl acetate and ethylene are 86.09 g/mol and 28.05 g/mol respectively

so

moles of vinyl acetate = wt. of vinyl acetate / molecular weights of vinyl acetate

moles of vinyl acetate = 12.9 g / 86.09 g/mol

moles of vinyl acetate = 0.1498 mol

moles of Ethylene = wt. of Ethylene / molecular weights of Ethylene

moles of Ethylene = 87.1 g / 28.05  d/mol

moles of Ethylene  = 3.1052 mol

Total moles = 0.1498 mol + 3.1052 mol = 3.255 mol

Next we calculate the mole percent;

mole percent of vinyl acetate X_{V} = moles of vinyl acetate / total  moles

X_{V} = (0.1498 mol / 3.255 mol) × 100

X_{V}  = 4.6%

mole percent of Ethylene X_{E} = moles of Ethylene / total  moles

X_{E}  = (3.1052 mol / 3.255 mol) × 100

X_{E}  = 95.397% ≈ 95.4%

we know that, mean repeat unit molar mass for a sample = ∑X_{i}M_{i}

where X_{i} is the fraction ratio and M_{i} is the molecular  weight

so or the PEVA

mean repeat unit molar mass M = ( X_{V}M_{V}) + ( X_{E}M_{E})

so we substitute

M = ( 4.6% × 86.09) + ( 95.4% × 28.05 )

M = 3.96014 + 26.7597

M = 30.72 g/mol

Therefore, The mean repeat unit molar mass for PEVA is 30.72 g/mol

b)

Degree of polymerization

DP_{n} = \frac{M_{n} }{M}

where M_{n} is the number average molecular weight ( 39,870 g/mol )

so we substitute

DP_{n} = 39,870 g/mol / 30.72 g/mol

DP_{n}  = 1297.85 ≈ 1300   { 3 significance figure }

Therefore, degree of polymerization of the copolymer is 1300

5 0
2 years ago
Other questions:
  •  A reaction container holds 5.77 g of P4 and 5.77 g of O2.
    6·1 answer
  • What is the molarity of silver ion in the final solution
    7·1 answer
  • In the laboratory you dissolve 15.9 g of barium chloride in a volumetric flask and add water to a total volume of 375 ml. what i
    8·1 answer
  • Americium-241 is used in smoke detectors. it has a first order rate constant for radioactive decay of k=1.6×10−3yr−1. by contras
    10·1 answer
  • Is air a molecule or a mixture
    10·1 answer
  • Describe 2 similarities of metals and nonmetals
    10·1 answer
  • The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0 °c is 4.48. what is the value of ka for hbro?
    13·1 answer
  • A neutralization reaction is taking place between solutions of phosphoric acid and calcium
    10·1 answer
  • You are managing a city that needs to upgrade its disinfection basin at your 40 MGD surface water drinking water treatment plant
    11·1 answer
  • Whoever answers my question correctly I'll give 50 points​
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!