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olganol [36]
3 years ago
11

Which of the following represents alpha decay?

Chemistry
1 answer:
aliya0001 [1]3 years ago
8 0

Answer: b

Explanation: alpha decay or particle consist of two protons and two neutrons hence it is a helium nucleus.

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William adds two values, following the rules for using significant figures in computations. He should write the sum of these two
Alinara [238K]
It seems that you have missed the necessary options for us to answer this question, but anyway here is the answer. William adds two values, following the rules for using significant figures in computations. He should write the sum of these two numbers by using the same number of decimal places as the least precise value. Hope this helps.
7 0
3 years ago
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How many moles of magnesium are in 3. 01 x 10^22 atoms of magnesium.
marshall27 [118]

Answer:

Explanation:

1 mol of anything is 6.02 * 10^23 atoms (in this case)

x mol of 3.01 * 10^22

Set up the proportion

1/x = 6.02*10^23 / 3.01 * 10^22                 Cross multiply

x*6.02 * 10^23 = 1 * 3.01 * 10^22               Divide by 6.02*10^23

x = 3.01 * 10^22 / 6.02*10^23

x = 1/(2 * 10)

x = 1/20 mol

x = 0.05 mol

5 0
2 years ago
Compute the ionization energy for a single atom of hydrogen
cricket20 [7]
The ionization energy<span> for </span>hydrogen<span> is 1312 kilojoules per mole. This is the same ... Electrically neutral </span>atoms<span> include a </span>single<span> proton and electron held together.</span>
6 0
3 years ago
A solution is prepared by dissolving 38.6 g sucrose (C12H22O11) in 495 g of water. Determine the mole fraction of sucrose if the
stiks02 [169]

Answer:

4.09×10⁻³ is the mole fraction of sucrose

Explanation:

Mole fraction = Moles of solute or solvent/ Total moles

Let's convert the mass to moles (mass / molar mass)

38.6 g / 342 g/m = 0.113 moles of sucrose

495 g / 18 g/m = 27.5 moles of water

Total moles = 0.113 m + 27.5 m = 27.0613 moles

Mole fraction of sucrose = Moles of sucrose / Total moles

0.113 m / 27.0613 moles = 4.09×10⁻³

8 0
3 years ago
How many grams of mercury are needed to react completely with 157g of sulfur to form hgs?
Salsk061 [2.6K]
<span>To solve this we need to balance the equations first.
 So Hg + S --> HgS is balanced
 One mole of Hg requires one mole of S to form one mole of HgS.
 Number of moles of Sulphur = mass/ molar mass = 157/32 = 4.906
So 4.90 moles of S reacts with 4.90 moles of Hg.
Hence there are 4.90 moles of 4.90 of Hg.
 Mass = number of moles * molar mass of Hg
Mass = 4.906 * 200.59 = 982.891g</span>
8 0
3 years ago
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