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klemol [59]
3 years ago
12

An atom bonds with another atom. What is the best classification for this reaction?

Chemistry
2 answers:
Galina-37 [17]3 years ago
7 0
<h3><u>Answer;</u></h3>

Chemical bond

<h3><u>Explanation;</u></h3>
  • <em><u>Chemical bond is an attraction that is formed between atoms or molecules which enables formation of chemical compounds. </u></em>
  • <em><u>Chemical bonds result from attraction of atoms to each other through the sharing of electrons, exchanging of electrons or the transfer of electrons or electrostatic forces.</u></em>
  • Chemical bonds may be classified as metallic bond, ionic bond or covalent bond.
  • Ionic bonds occur when electrons are transferred from one atom to another, and the result is attraction between the resulting oppositely charged ions. Covalent bonds occurs as a result of sharing of electrons between non-metal atoms. Metallic bond occur in metals as a result of positively charged nucleus and a sea of electrons in the atoms.
OlgaM077 [116]3 years ago
4 0

Explanation:

When an atom bonds with another atom then it results in the formation of a chemical bond.

This formation of bond could be due to transfer or sharing of electrons.

When a chemical bond is formed due to transfer of electrons then this type of bond is known as ionic bond.

When a chemical bond is formed due to sharing of electrons then this type of bond is known as covalent bond.

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Answer : The final pressure of the basketball is, 0.990 atm

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

or,

\frac{P_1}{P_2}=\frac{T_1}{T_2}

where,

P_1 = initial pressure = 1.10 atm

P_2 = final pressure = ?

T_1 = initial temperature = 28.0^oC=273+28.0=301.0K

T_2 = initial temperature = -2.00^oC=273+(-2.00)=271.0K

Now put all the given values in the above equation, we get:

\frac{1.10atm}{P_2}=\frac{301.0K}{271.0K}

P_2=0.990atm

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What volume of air at 25°C and 1.00 atm can he stored in a 10.0 L high-pressure air tank if compressed to 25°C and 175 atm?
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Answer:

1750L

Explanation:

Given

Initial Temperature = 25°C

Initial Pressure = 175 atm

Initial Volume = 10.0L

Final Temperature = 25°C

Final Pressure = 1 atm

Final Volume = ?

This question is an illustration of ideal gas law.

From the given parameters, the initial temperature and final temperature are the same; this implies that the system has a constant temperature.

As such, we'll make use of Boyle's Law to solve this;

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1750 atm L = 1 atm * V₂

1750 L = V₂

Hence, the final volume that can be stored is 1750L

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