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klemol [59]
3 years ago
12

An atom bonds with another atom. What is the best classification for this reaction?

Chemistry
2 answers:
Galina-37 [17]3 years ago
7 0
<h3><u>Answer;</u></h3>

Chemical bond

<h3><u>Explanation;</u></h3>
  • <em><u>Chemical bond is an attraction that is formed between atoms or molecules which enables formation of chemical compounds. </u></em>
  • <em><u>Chemical bonds result from attraction of atoms to each other through the sharing of electrons, exchanging of electrons or the transfer of electrons or electrostatic forces.</u></em>
  • Chemical bonds may be classified as metallic bond, ionic bond or covalent bond.
  • Ionic bonds occur when electrons are transferred from one atom to another, and the result is attraction between the resulting oppositely charged ions. Covalent bonds occurs as a result of sharing of electrons between non-metal atoms. Metallic bond occur in metals as a result of positively charged nucleus and a sea of electrons in the atoms.
OlgaM077 [116]3 years ago
4 0

Explanation:

When an atom bonds with another atom then it results in the formation of a chemical bond.

This formation of bond could be due to transfer or sharing of electrons.

When a chemical bond is formed due to transfer of electrons then this type of bond is known as ionic bond.

When a chemical bond is formed due to sharing of electrons then this type of bond is known as covalent bond.

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Lady_Fox [76]

Answer:

not the best but that is alright

Explanation:

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3 0
2 years ago
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One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na3(CO3)(HCO3)·2H2O. 2Na3(CO3)(HCO
zhenek [66]
Percentage yield = (actual yield / theoretical yield) x 100%

The balanced equation for the decomposition is,
 2Na₃(CO₃)(HCO₃)·2H₂O(s) → 3Na₂CO₃(s) + CO₂(g) + 5H₂<span>O(g)

The stoichiometric ratio between </span>Na₃(CO₃)(HCO₃)·2H₂O(s)  and Na₂CO₃(s) is 2 : 3

The decomposed mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 1000 kg
                                                                                     = 1000 x 10³ g

Molar mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 226 g mol⁻¹
moles of Na₃(CO₃)(HCO₃)·2H₂O(s) = mass / molar mass
                                                         = 1000 x 10³ g / 226 g mol⁻¹
                                                         = 4424.78 mol

Hence, moles of Na₂CO₃ formed = 4424.78 mol x \frac{3}{2}
                                                     = 6637.17 mol

Molar mass of Na₂CO₃ = 106 g mol⁻¹

Hence, mass of Na₂CO₃ = 6637.17 mol x 106 g mol⁻¹
                                        = 703540.02 g
                                        = 703.540 kg

Hence, the theoretical yield of Na₂CO₃ =  703.540 kg
Actual yield of Na₂CO₃ = 650 kg

Percentage yield = (650 kg / 703.540 kg) x 100%
                            = 92.34%
7 0
3 years ago
What Is the Connection Between Sulfuric Acid and Hydrochloric Acid?
d1i1m1o1n [39]
They are both strong, corrosive acids. Hydrochloric acid can be synthesize using table salt and sulfuric acid.
7 0
3 years ago
."A ternary covalent compound consists of 3 types of nonmetallic elements in its chemical formula." Which is NOT an example of a
muminat
The answer is a hope this helps
3 0
2 years ago
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VladimirAG [237]

Answer:

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  • 2. Shape: the sheet can be formed into a paper ball or any other shape (using origami for example).

  • 3. Color: You can use crayons to paint the sheet and change its color.

Explanation:

<em>Physical changes</em> do not change the chemical properties. They do not transform the compounds that form the substances. They do not break and or form chemical bonds.

When you change the form, the state (solid, liquid or gas), the color, you are just changing physical properties.

Only chemical changes change the compounds that form the substance. For instance, if you burn the <em>sheet of paper</em>, then you are causing a chemical change because the organic matter in the paper will react with oxygen forming CO₂ and water, but by cutting, folding, smashing, or coloring with crayons, the compounds in the<em> sheet of paper</em> do not change.

6 0
3 years ago
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