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rewona [7]
3 years ago
12

Balance the following chemical equation.​​​​​​​(2)

Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
8 0

Balanced chemical equation:

2 C₃H₆N₆ (l) + 9 O₂ (g) → 6 CO₂ (g) + 6 H₂O (g) + 6 N₂ (g)

Explanation:

The correct chemical reaction is:

C₃H₆N₆ (l) + O₂ (g) → CO₂ (g) + H₂O (g) + N₂ (g)

To balance the chemical equation the number of atoms of each element entering the reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.

Balanced chemical reaction:

C₃H₆N₆ (l) + (9/2) O₂ (g) → 3 CO₂ (g) + 3 H₂O (g) + 3 N₂ (g)

To have integer numbers we multiply the equation with 2 to obtain:

2 C₃H₆N₆ (l) + 9 O₂ (g) → 6 CO₂ (g) + 6 H₂O (g) + 6 N₂ (g)

Learn more about:

balancing chemical equations

brainly.com/question/14027933

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What is dependent on the ability of water molecules to form hydrogen bonds with other molecules besides water
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The ability of water molecules to form hydrogen bonds with other molecules besides water is the universality of water as a solvent.

Explanation:

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3 years ago
Cecil writes the equation for the reaction of hydrogen and oxygen below.
Wittaler [7]

Answer:

C) to show that atoms are conserved in chemical reactions

Explanation:

When writing a chemical reaction, we should always consider the Mass Conservation Law, which basically states that; in an isolated system; the total mass should remain constant, this is, the total mass of the reactives should be equal to the total mass of the products

For this case, we should add the apporpiate coefficients in order to be in compliance with this law:

2H₂ + O₂ → 2H₂O

So, we can check the above statement:

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For product (right side):

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5 0
3 years ago
Calculate the change in pH when 71.0 mL of a 0.760 M solution of NaOH is added to 1.00 L of a solution that is 1.0O M in sodium
Eddi Din [679]

Explanation:

It is known that pK_{a} value of acetic acid is 4.74. And, relation between pH and pK_{a} is as follows.

                    pH = pK_{a} + log \frac{[CH_{3}COOH]}{[CH_{3}COONa]}

                          = 4.74 + log \frac{1.00}{1.00}

So, number of moles of NaOH = Volume × Molarity

                                                   = 71.0 ml × 0.760 M

                                                    = 0.05396 mol

Also, moles of  CH_{3}COOH = moles of CH_{3}COONa

                                          = Molarity × Volume

                                          = 1.00 M × 1.00 L

                                          = 1.00 mol

Hence, addition of sodium acetate in NaOH will lead to the formation of acetic acid as follows.

            CH_{3}COONa + NaOH \rightarrow CH_{3}COOH

Initial :    1.00 mol                                  1.00 mol

NaoH addition:               0.05396 mol

Equilibrium : (1 - 0.05396 mol)    0           (1.00 + 0.05396 mol)

                    = 0.94604 mol                       = 1.05396 mol

As, pH = pK_{a} + log \frac{[CH_{3}COONa]}{[CH_{3}COOH]}

               = 4.74 +  log \frac{0.94604}{1.05396}

               = 4.69

Therefore, change in pH will be calculated as follows.

                         pH = 4.74 - 4.69

                               = 0.05

Thus, we can conclude that change in pH of the given solution is 0.05.

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