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3 years ago

Balance the following chemical equation.(2)

Chemistry

1 answer:

Angelina_Jolie [31]3 years ago

8 0

Balanced chemical equation:

2 C₃H₆N₆ (l) + 9 O₂ (g) → 6 CO₂ (g) + 6 H₂O (g) + 6 N₂ (g)

Explanation:

The correct chemical reaction is:

C₃H₆N₆ (l) + O₂ (g) → CO₂ (g) + H₂O (g) + N₂ (g)

To balance the chemical equation the number of atoms of each element entering the reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.

Balanced chemical reaction:

C₃H₆N₆ (l) + (9/2) O₂ (g) → 3 CO₂ (g) + 3 H₂O (g) + 3 N₂ (g)

To have integer numbers we multiply the equation with 2 to obtain:

2 C₃H₆N₆ (l) + 9 O₂ (g) → 6 CO₂ (g) + 6 H₂O (g) + 6 N₂ (g)

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balancing chemical equations

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What has research determined about the orbit of an electron around a nucleus

polet [3.4K]

Hello,

Here is your answer:

The proper answer to this question is that "e<span>ach sub-level electron type has a unique path where it will likely to be found".

If you need anymore help feel free to ask me!

Hope this helps!</span>

4 0

3 years ago

Read 2 more answers

For an enzyme that displays Michaelis-Menten kinetics, what is the reaction velocity, v(as a percentage of Vmax), observed at:a)

fiasKO [112]

Answer:

a) 50% of the maximum velocity

b) 33.33% of the maximum velocity

c) 9.09% of the maximum velocity

d) 66.66% of the maximum velocity

e) 90.9% of the maximum velocity

Explanation:

The Michaelis-Menten kinetis is represented by

v = Vmax*S/(Km+S)

where

v= reaction rate

S= Substrate's concentration

Vmax= maximum rate of reaction

Km= constant

a) for S=Km

v = Vmax*Km/(2Km) = Vmax/2

v/Vmax = 1/2= 50% of the maximum velocity

b) for S=Km/2

v = Vmax*(Km/2)/(3/2Km) = Vmax/3

v/Vmax = 1/3= 33.33% of the maximum velocity

c) for S= 0.1*Km=Km/10

v = Vmax*(Km/10)/(11/10Km) = Vmax/11

v/Vmax = 1/11= 9.09% of the maximum velocity

d) for S=2*Km

v = Vmax*(2*Km)/(3*Km) = (2/3)* Vmax

v/Vmax = 2/3 = 66.66% of the maximum velocity

d) for S=10*Km

v = Vmax*(10*Km)/(11*Km) = (10/11)* Vmax

v/Vmax = 10/11 = 90.9 % of the maximum velocity

7 0

3 years ago

* Need ASAP * Explain the relationship between percent composition, Empirical formula, and molecular formula.

sweet-ann [11.9K]

By dividing the percentage composition with the molar mass of that element we will get the empirical formula. Then using that empirical formula and formula mass we can find the molecular formula.

<u>Explanation:</u>

The chemical properties of any substance are defined obviously by the different types and relative amounts of atoms constituting its primary entities (in case of covalent compounds the primary entities are molecules and ions in the event of ionic compounds).

A percent composition of any compound gives the mass percent of each element present in the compound; in addition to that frequently it is determined experimentally and utilized to derive an empirical formula of any compound. An empirical formula mass of any covalent compound could be comparable with the molar or molecular mass of a compound to acquire a molecular formula.

5 0

3 years ago

Please help!!!

Aloiza [94]

Answer:

3 × 10¯¹⁰

Explanation:

9×10² ÷ 3×10¹²

The above expression can be simplified as follow:

9×10² ÷ 3×10¹²

Recall:

9 = 3²

9×10² ÷ 3×10¹² = 3²×10² ÷ 3×10¹²

Recall:

a^m ÷ a^n = a^(m – n)

3²×10² ÷ 3×10¹² = 3^(2 – 1) × 10^(2 – 12)

= 3¹ × 10¯¹⁰

Recall:

a¹ = a

3¹ × 10¯¹⁰ = 3 × 10¯¹⁰

4 0

3 years ago

For many purposes we can treat propane as an ideal gas at temperatures above its boiling point of . Suppose the temperature of a

irina [24]

Answer:

See explaination

Explanation:

please kindly see attachment for the step by step solution of the given problem

4 0

3 years ago

Balance the following chemical equation.​​​​​​​(2)

Balance the following chemical equation.(2)