The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
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brainly.com/question/1397278
Answer:
308 cm³
Step-by-step explanation:
The volume (V) of a rectangular prism ( cuboid ) is
V = lbh ( l is the length, b the breadth and h the height )
Here l = 11, b = 7 and h = 4, thus
V = 11 × 7 × 4 = 308 cm³
Answer:
The equation of a right triangle is given by a2 + b2 = c2, where either a or b is the height and base of the triangle and c is the hypotenuse. Using the Pythagorean Theorem, finding the missing side of a triangle is pretty simple and easy. The two special right triangles include: 45°; 45°; 90° Triangle.
a correct answer that guy ☝ is rude can i get brainliest for answering
Answer:
Angles RSQ and WVX are alternate interior angles.
Hope this helps!
<span>oh i get it well to make two equations equal you have to find something that fits in x. you see the eqal sign? that is seperating the two equations that you have to make equal </span>
