Question

What mass of oxygen reacts during the incomplete combustion of 18.0 g of propane?

Answer 1

Answer:

45.82 gm O2

Explanation:

From your balanced equation in the first part, you can see that 2 moles propane  need 7 moles O2

Find the number of moles of propane in 18 gm

   mole wt of propane = ~  12 * 3 + 8 *1 = 44 gm/mole

      18 gm /  44 gm/mole  =  9/22 gm/mole  propane

            we need 7/2 of this as O2 moles    7/2 * 9/22 = 1.432moles of O2

 O2   mole weight =~ 32

       1.432 moles * 32 gm/mole = 45.82 gm O2