The mass in grams of nitric acid that is required to react with 454g C7H8 is 932.72 grams
calculation
find the moles of C7H8 used
moles = mass/molar mass
= 454 g/92 = 4.935 moles
balanced reacting equation
C7H8 +3 HNO3 = C7H5N3O6 +3 H20
by use of mole ratio between C7H8 to HNo3 which is 1:3 the moles of HNO3 =4.935 x3 = 14.805 moles
mass of HNo3 = moles x molar mass
= 14.805 x 63 = 932.72 grams
part B
the mass of C7H5N3o6 = 2045.5 grams
calculate the moles of C7H8
= 829 g/92 g/mol = 9.011 moles
by use of mole ratio between C7H8 to C7H5N3O6 which is 1:1 the moles of C7H5N3O6 is also = 9.011 moles
mass of C7H5N3O6 is therefore = moles x molar mass
=9.011 x227 = 2045.5 grams
Answer:
I believe the answer The case study was influenced by bias, and led to incorrect conclusions being drawn. plz correct me if I am wrong
Explanation:
Answer:
86.0 mL
Explanation:
i just did the USA test prep
