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nirvana33 [79]
3 years ago
15

The molar enthalpy of fusion for water is 6.008 kJ/mol. How much energy is released when 4.81 mol of water freezes?

Chemistry
1 answer:
choli [55]3 years ago
3 0

Answer: The energy released when 4.81 mol of water freezes is 28.9kJ

Explanation:

Latent heat of fusion is the amount of heat required to convert 1 mole of solid to liquid at atmospheric pressure or energy released when 1 mole of liquid freezes to solid at atmospheric pressure.

\Delta H_{fusion} = enthalpy change for fusion = 6.008 KJ/mole

Energy released when 1 mole of water freezes = 6.008 kJ

Energy released when 4.81 moles of water freezes = \frac{6.008 kJ}{1}\times 4.81mol=28.9kJ

Therefore, the energy released when 4.81 mol of water freezes is 28.9kJ

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Answer:

The answer is "33.95 \bold{ \frac{kj}{mol}}\\".

Explanation:

Formula:

\bigtriangleup G_0= -R \times T l_n \times K_{eq}\\

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Given value:

T =35^{\circ} C\\

convert temperature celsius (°C) to Kelvin (K):

= (273+45) \ kelvin \\\\= 318 \ Kelvin \\\\= 318 \ K

R = 8.314 \ \ \frac{J}{ mol \cdot K}

\bigtriangleup G_0= -(8.314 ) \times 31.8 \times  l_n (2.65\times 10^{-6})\\

        =-(8.314 ) \times 31.8T l_n \times (2.65\times 10^{-6})\\\\

After solving the value it will give:

        = 33.95  \bold{ \frac{kj}{mol}}\\

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Which arrow in the diagram represents the burning of fossil fuels? Choose 1 answer: Choose 1 answer: (Choice A) A arrow 1 (Choic
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Answer: arrow 4

Explanation:

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3 years ago
A student is examining a bacterium under the microscope. The E. coli bacterial cell has a mass of m = 1.80 fg (where a femtogram
egoroff_w [7]

Answer:

Δx ≥  1.22 *10^-10m

Explanation:

<u>Step 1:</u> Data given

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Velocity of v = 8.00 μm/s (= 8.00 * 10^-6 m/s)

Uncertainty in the velocity = 3.00 %

E. coli bacterial cells are around 1 μm = 10^−6 m in length

<u>Step 2:</u> Calculate uncertainty in velocity

Δv = 0.03 * 8*10^-6 m/s =2.4 * 10^-7 m/s

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According to Heisenberg uncertainty principle,

Δx *Δp ≥ h/4π

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with Δx = TO BE DETERMINED

with m = 1.8 *10^-18 kg

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with h = constant of planck = 6.626 *10^-34

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6 0
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A student is given an antacid tablet that weighed 5.6832 g. The tablet was crushed and 4.3628 g of he antacid was added to 200 m
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Answer:

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5.6832g antacid * (191.67 ml acid / 4.3628 g antacid) = 249.68 ml acid

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