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marishachu [46]
3 years ago
10

A gas has a density of 0.902 g l at stp what is the molar mass of this gas

Chemistry
1 answer:
S_A_V [24]3 years ago
8 0
According to the molar gas volume, one mole of a gas occupies a volume of 22400 cm³ or 22.4 liters. The standard temperatures and pressures conditions are temperature of 0 degrees Celsius or 273 kelvin and an absolute pressure of 103.325 kPa or 1 atm. In this case, the density is 0.902 g/l and the volume is 22400 cm³,
therefore, the molar mass will be;
0.902 g/ L ×22.4 liters = 20.2048g 
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Rasek [7]

Explanation:

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What is the partial pressure of carbon dioxide in a container that contains 3.63 mol of oxygen, 1.49 mol of nitrogen, and 4.49 m
lana66690 [7]

Answer:

Partial pressure of CO₂ is 406.9 mmHg

Explanation:

To solve the question we should apply the concept of the mole fraction.

Mole fraction = Moles of gas / Total moles

We have the total moles of the mixture, if we have the moles for each gas inside. (3.63 moles of O₂, 1.49 moles of N₂ and 4.49 moles of CO₂)

Total moles = 3.63 mol O₂ + 1.49 mol N₂ + 4.49 mol CO₂ = 9.61 moles

To determiine the partial pressure of CO₂ we apply

Mole fraction of CO₂ → mol of CO₂ / Total moles = P. pressure CO₂ / Total P

Partial pressure of CO₂ = (mol of CO₂ / Total moles) . Total pressure

We replace values: (4.49 moles / 9.61 moles) . 871 mmHg = 406.9 mmHg

6 0
3 years ago
Read 2 more answers
The Kp for the reaction below is 1.49 × 108 at 100.0°C:
Anna007 [38]
Kp= (COCl2)/[(CO)(Cl2)]= 1.49 x 10^8

1.49 x 10^8= (COCl2/((2.22x10-4)(2.22x10-4))

COCl2= 1.49x10^8 x ((2.22x10-4)(2.22x10-4))= 7.34 atm
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