Complete Question
An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an electron is 1.60218 × 10−19 C and its mass is 9.10939 × 10−31 kg. How strong a magnetic field must be experienced by the electron if its path is a circle of radius 5.4 cm?
Answer:
The magnetic field strength is 
Explanation:
The work done by the potential difference on the electron is related to the kinetic energy of the electron by this mathematical expression
Making v the subject
![v = \sqrt{[\frac{2 \Delta V * q }{m}] }](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5B%5Cfrac%7B2%20%5CDelta%20V%20%2A%20q%20%7D%7Bm%7D%5D%20%7D)
Where m is the mass of electron
v is the velocity of electron
q charge on electron
is the potential difference
Substituting values
![v = \sqrt{\frac{2 * 5.9 *10^3 * 1.60218*10^{-19} }{9.10939 *10^{-31]} }](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cfrac%7B2%20%2A%205.9%20%2A10%5E3%20%2A%201.60218%2A10%5E%7B-19%7D%20%7D%7B9.10939%20%2A10%5E%7B-31%5D%7D%20%7D)
f
For the electron to move in a circular path the magnetic force[
] must be equal to the centripetal force[
] and this is mathematically represented as
making B the subject
r is the radius with a value = 5.4cm = 
Substituting values
Answer:
100 m/s
Explanation:
here we use the wave equation which states that the velocity is equal to the product of the frequency and the wavelength.
so v = 50 × 2
v = 100 m/s
Rate of speed, probs is the answer
1) The correct answer is
<span>C) The particles are not able to move out of their positions relative to one another, but do have small vibrational movements.
In solids, in fact, particles are bound together so they cannot move freely. However, they can move around their fixed position with small vibrational movements, whose intensity depends on the temperature of the substance (the higher the temperature, the more intense the vibrations). For this reason, we say that matter moves also in solid state.
2) The correct answer is
</span><span>A) increase the concentration of both solutions
In fact, when we increase the concentration of both solutions, we increase the number of particles that react in both solutions; as a result, the speed of the reaction will increase.
3) The correct answer is
</span><span>C) gas → liquid → solid
In gases, in fact, particles are basically free to move, so the intermolecular forces of attraction are almost negligible. In liquids, particles are still able to move, however the intermolecular forces of attraction are stronger than in gases. Finally, in solids, particles are bound together, so they are not free to move and the intermolecular forces of attraction are very strong. </span>
