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alex41 [277]
3 years ago
14

A pendulum has 294 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o

f its swing
Physics
1 answer:
baherus [9]3 years ago
6 0

Newton's law of conservation states that energy of an isolated system remains a constant. It can neither be created nor destroyed but can be transformed from one form to the other.


Implying the above law of conservation of energy in the case of pendulum we can conclude that at the bottom of the swing the entire potential energy gets converted to kinetic energy. Also the potential energy is zero at this point.


Mathematically also potential energy is represented as


Potential energy= mgh


Where m is the mass of the pendulum.


g is the acceleration due to gravity


h is the height from the bottom z the ground.


At the bottom of the swing,the height is zero, hence the potential energy is also zero.


The kinetic energy is represented mathematically as


Kinetic energy= 1/2 mv^2


Where m is the mass of the pendulum


v is the velocity of the pendulum


At the bottom the pendulum has the maximum velocity. Hence the kinetic energy is maximum at the bottom.


Energy can neither be created e destroyed. It can only be transferred from one form to another. Implying this law and the above explainations we conclude that at the bottom of the pendulum,the potential energy=0 and the kinetic energy=294J as the entire potential energy is converted to kinetic energy at the bottom.



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A resistor and a capacitor are connected in series across an ideal battery having a constant voltage across its terminals. Long
tino4ka555 [31]

Answer:

A) equal to the battery's terminal voltage.

Explanation:

When the capacitor is fully charged after long hours of charging , its  potential becomes equal to the emf of the battery and its polarity is opposite to that of battery . Hence net emf becomes equal . The capacitor itself becomes a battery which is connected in the circuit with opposite polarity . This results in the net emf and  current becoming zero . There is no charging current when the capacitor is fully charged .

4 0
3 years ago
During the first 14 minutes of a 1.0 hour trip, a car has an average speed 36 km/h. What must the average speed in km/h of the c
oksian1 [2.3K]

Answer:

85.5 km/h

Explanation:

t_{1} = time interval for first phase = 14 min = \frac{14}{60} h = 0.233 h

t_{2} = time interval for second phase = 46 min = \frac{46}{60} h = 0.767 h

v = average speed for the entire trip = 74 km/h

v_{1} = average speed in first phase = 36 km/h

v_{2} = average speed in second phase

d_{1} = distance traveled in first phase

d_{2} = distance traveled in first phase

average speed is given as

v = \frac{d_{1} + d_{2}}{t_{1} + t_{2}}

v = \frac{v_{1} t_{1} + v_{2} t_{2}}{t_{1} + t_{2}}

74 = \frac{(36) (0.233) + v_{2} (0.767)}{0.233 + 0.767}

74 = (36) (0.233) + v_{2} (0.767)

v_{2} = 85.5 km/h

4 0
3 years ago
Suppose that the half-life of an element is 1000 years. How many half-lives will it take before one-eighth of the original sampl
34kurt

Answer:

3

Explanation:

The half-life of a radioactive isotope is the time it takes for the mass of the sample to halve.

This can be rewritten as follows:

m(t) = m_0 (\frac{1}{2})^n

where

m(t) is the mass of the sample at time t

m0 is the original mass of the sample

n is the number of half-lives that passed

We see that if we take n=3, the amount of original sample left is

m(t) = m_0 (\frac{1}{2})^3 = m_0 (\frac{1}{8})

So 3 (3 half-lives) is the correct answer.

3 0
3 years ago
Read 2 more answers
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