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Tatiana [17]
3 years ago
10

Calculate

Physics
1 answer:
Fed [463]3 years ago
8 0
The speed of the spacecraft in this orbit
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A science teacher tells her class that their final project requires students to measure a specific variable and determine the ve
iogann1982 [59]

Answer:

Yes

Explanation:

The velocity measured by Jennifer and Johnny is

v_m = 34.87 m/s

The actual velocity is

v=34.15 m/s

We can calculate the % error of the students measurement as follows:

Err = \frac{v_m - v}{v}\cdot 100 = \frac{34.87 m/s-34.15 m/s}{34.15 m/s}\cdot 100 =0.021 \cdot 100 = 2.1 \%

Which is lower than the 2.5% maximum error required, so the two students will pass the test.

4 0
3 years ago
Potential energy is due to_blank_?
nadezda [96]

gravity? I am not completly sure but this is my best guess

7 0
3 years ago
Read 2 more answers
The arrival time of an elevator in a 12-story dormitory is equally likely at any time range during the next 5.5 minutes. (a) Cal
Bumek [7]

Answer:

(a). 2.8 minutes.

(b). 0.4732

Explanation:

Without mincing words, let's dive straight into the solution to the question.

So, for the part (a), the expected arrival time can be calculated as given below.

The distribution falls between the ranges of 0(lower boundary) to 5.5minutes(upper boundary).

Therefore, the expected time = (0 + 5.5)÷ 2 = 2.75 minutes = 2.8 minutes(to 2 decimal places).

(b). The probability that an elevator arrives in less than 2.6 minutes can be calculated as given below;

Recall: We have that the upper boundary = 0 and the lower boundary = 5.5 minutes for the distribution. Also, the upper limit is equal to 2.6 minutes and the lower limits = 0 minutes.

Therefore, 1/ (5.5 - 0) = 1/5.5 = 0.182.

Therefore, the probability that an elevator arrives in less than 2.6 minutes = 0.182 ( 2.6 - 0).

The probability that an elevator arrives in less than 2.6 minutes = ( 0.182 × 2.6).

The probability that an elevator arrives in less than 2.6 minutes = 0.4732.

6 0
3 years ago
Which of the following is the best thing to do after reading this
meriva

Look for scientific research about whether these claims are correct or not.

Explanation:

The best thing to do after reading this  advertisement is to look for scientific research about whether these claims are correct or not.

7 0
3 years ago
A drag racer starts from rest and accelerates at 7.4 m/s2. How far will he travel in 2.0 seconds?
3241004551 [841]

Using the kinematic equation below we can determine the distance traveled if t=2, a=7.4m/s^2.  First we must determine the final velocity:

v_{final}=v_{initial}+\frac{1}{2}at\\\\v_{final}=0+(7.4m/s^2)(2s)=34.8m/s

Now we will determine the distance traveled:

v_{final}^2=v_{initial}^2+2a \Delta x\\\\\Delta x = \frac{v_{final}^2}{2a} =\frac{(34.8)^2}{(2)(7.4)}=81.83 m

Therefore, the drag racer traveled 81.83 meters in 2 seconds.

4 0
3 years ago
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