If y = cos(kt), then its first two derivatives are
y' = -k sin(kt)
y'' = -k² cos(kt)
Substituting y and y'' into 49y'' = -16y gives
-49k² cos(kt) = -15 cos(kt)
⇒ 49k² = 15
⇒ k² = 15/49
⇒ k = ±√15/7
Note that both values of k give the same solution y = cos(√15/7 t) since cosine is even.
56,900 but I'm only 50% sure I don't know about the other 50% sorry If its wrong.
Equivalent lines for sure
Answer:
12
Step-by-step explanation:
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Hello!
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❖ Mai has $4.90 left.
Add $4.35 and $5.25 to get the total amount that she spent:
$4.35 + $5.25 = $9.60
Then subtract to get the amount of money left:
$14.50 - $9.60 = $4.90
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