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QveST [7]
2 years ago
15

Pick the correct answer Help me please thank you :)

Mathematics
1 answer:
Andrej [43]2 years ago
4 0
Answer: D
Steps: In partially legible pic below. Sorry not the best explanation

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In ΔIJK, k = 57 inches, i = 37 inches and ∠J=141°. Find ∠I, to the nearest degree.
Sonbull [250]

Answer:

<I= 15degrees

Step-by-step explanation:

Using the cosine rule formulae;

j² = i²+k²-2i cos <J

j² = 37²+57² - 2(37)(57)cos <141

j² = 1369+ 3249- 4218cos <141

j² = 4618- 4218cos <141

j² = 4618-(-3,278)

j²= 7,896

j = √7,896

j = 88.86inches

Next is to get <I

i² = j²+k²-2jk cos <I

37² = 88.86²+57² - 2(88.86)(57)cos <I

1369 = 7,896.0996+ 3249- 10,130.04cos <I

1369 = 11,145.0996 - 10,130.04cos <I

1369 - 11,145.0996 = - 10,130.04cos <I

-9,776.0996=- 10,130.04cos <I

cos <I =9,776.0996 /10,130.04

cos<I = 0.96506

<I = 15.19

<I= 15degrees

8 0
2 years ago
Polynomial are closed under multiplication. What does that mean?
Y_Kistochka [10]

Answer:

look this link up

https://mathbitsnotebook.com/Algebra1

3 0
2 years ago
Please help me with this math problem
iren [92.7K]

Answer:

The third one

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Plz help me well mark brainliest if correct...?????
galben [10]

Answer:

Option B, Shows change over time

Step-by-step explanation:

Since the slope of a line graph could be found out by the formula;

Change y / Change in x...

<u>This represents change over time</u>

Hope this helps!

8 0
2 years ago
Explain how you can use the inscribed angle theorem to justify its second corollary, that an angle inscribed in a semicircle is
mihalych1998 [28]

Answer:

We find half the measure of the central angle of the circle. Where the given shape is a semi-circle, then the inscribed angle is half of 180, therefore, 90 degrees and a right angle is proven. We show this as Angle BAC is a RA 360 is the measure of circle 360/2 = 180 the semi circle Angle BAC is 180/2 = 90 degree.

Step-by-step explanation:

Hope it helps you!

7 0
3 years ago
Read 2 more answers
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