1/3 portion of the mixture, costing $\$6$ contains chocolate.
<h2>Calculation of the weight of the chocolate in the mixture:</h2>Assume that, in a mixture:
chocolate = x pound
nuts = y pound
mixture= x+y
The desired value is found by dividing the weight of the chocolate by the overall weight, or x/(x+y).
From the given data,
cost of x pound chocolate at $\$10$per pound = 10x
cost of y pound nuts at $\$4$ per pound = 4y
cost of x+y pound mixture at $\$6$ = 6(x+y)
As per condition,
⇒10x + 4y = 6(x+y)
⇒10x + 4y = 6x+ 6y
⇒4x = 2y
⇒y = 2x
The fraction of the chocolate in the mixture is
=
=
= 1/3
Therefore, chocolate makes 1/3 of the mixture's weight.
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Answer: or
Step-by-step explanation:
We can convert from mixed numbers to decimal numbers:
Since they cleaned up 8.2 kilograms of trash in one neighborhood and 11.5 kilograms in another neighborhood, the total trash they cleaned up was:
We know that they sent 1.25 kilograms to be recycled. Then, in order to calculate how many kilograms of trash they threw away, we must subtract the total kilograms of trash they cleaned up and the kilograms they sent to be recycled.
Then:
or
Answer:
B. The mean amount of emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg
Step-by-step explanation:
A Type II error is the failure to reject a false null hypothesis.
Given the null and alternate hypothesis of a fuel company which wants to test a new type of gasoline designed to have lower emissions.:
where is the mean amount of
emitted by burning one gallon of this new gasoline.
If the null hypothesis is false, then:
A rejection of the alternate hypothesis above will be a Type II error.
Therefore:
The Type II error is: (B) The mean amount of emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg.