X 9 =12 2 ⋅12 7 . x=?

Problems that equal 3r12

nevsk [136]

What does r mean. if r means multiply blank than 3*4 = 12

8 0

2 years ago

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HELPPP!!!

xxMikexx [17]

The angles ∠CFE and ∠AFB are vertically opposite angles. Then the value of x will be 6.

<h3>What is an angle?</h3>

Angle is the space between the line or the surface that meets. And the angle is measured in degree. For complete 1 rotation, the angle is 360 degrees.

Vertically opposite angle - When two lines intersect, then their opposite angles are equal.

We know that the angle ∠DFE is 90°.

Then the sum of the angle ∠CFD and ∠DFE will be

∠CFD + ∠DFE = 27° + 90°

∠CFD + ∠DFE = 117°

Then the angles ∠CFE and ∠AFB are vertically opposite angles. Then we have

∠CFD = ∠DFE

Put the values

21x - 9 = 117

21x = 126

x = 6

More about the angled link is given below.

brainly.com/question/15767203

#SPJ1

8 0

2 years ago

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

2 years ago

Can you help me with this?

77julia77 [94]

Answer:

the answer is a

3 0

2 years ago

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For each function, what is the output of the given input? for f(x) = 4x 7, find f(4)

shusha [124]

I hope this helps you

x =4

f (4)= 4.4+7 = 16+7=23

f (4)= 4.4-7=16-7=9

6 0

2 years ago