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Leto [7]
1 year ago
12

Find the difference. express the answer in scientific notation. (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 sup

erscript 11 baseline)
Mathematics
1 answer:
Georgia [21]1 year ago
7 0

The difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11

<h3>How to determine the notation</h3>

Given the expression

(5. 29 × 10^11) - (3. 86 × 10 ^11)

First, find the common factor

10^11 ( 5. 29 - 3. 86)

Then substract the values within the bracket

10^11 (1. 43)

Multiply with the factor, we have

⇒1. 43 × 10^11

Thus, the difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11

Learn more about index notation here:

brainly.com/question/10339517

#SPJ1

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Point A is at -7, -3. There are 12 points between A and B. What are possible coordinates for point B?
Finger [1]

Answer:

(5,9)

(-19, - 15)

(5, - 15)

(-19, 9)

Step-by-step explanation:

Given that :

Coordinate of point A = - 7, - 3

Number of points between point A and B = 12

Possible coordinate of point B

Possible coordinates of point B:

(-7, - 3) + 12 = (5, 9)

(-7, - 3) - 12 = (-19, - 15)

(-7, - 3) = (-7 +12, -3 - 12) = (5, - 15)

(-7, - 3) = (-7 - 12, - 3 + 12) = (-19, 9)

Hence possible coordinates of be are :

(5,9)

(-19, - 15)

(5, - 15)

(-19, 9)

8 0
3 years ago
The nth term of a sequence is represented by 3n4−10/6n4+7 . What is the limit of the the nth term as n becomes increasingly larg
Cerrena [4.2K]

Answer:

<h3>1/2</h3>

Step-by-step explanation:

Given the limit of the function expressed as;

\lim_{n \to \infty} \frac{3n^4-10}{6n^4+7} \\

To take the limit, we nee to divide through by the highest power of n first

\lim_{n \to \infty} \frac{3n^4/n^4-10/n^2}{6n^4/n^4+7/n^4}\\= \lim_{n \to \infty} \frac{3-10/n^2}{6+7/n^4}\\= \frac{3-10/(\infty)^2}{6+7/(\infty)^4}\\= \frac{3-0}{6-0}\\= \frac{3}{6}\\ = \frac{1}{2}\\

Hence the limit of the the nth term as n becomes increasingly large is 1/2

3 0
3 years ago
Someone please help me with this geometry proof question ASAP!
vivado [14]

Answer:

if ∠Q=∠R

draw an angular bisector from P to QR in which it intersect wit Qr at point S

now we have two triangle : QPS and RSP

in which angle : QPS=RPS ( PS is angular bisector)

and we have angle Q and angle R are equal

and PS is common side

this makes triangle QPS and RSP are congruent by AAS(angle angle side)

which also means that pQ=PR ( proved)

8 0
3 years ago
I need help on this question
Cloud [144]

Answer:

D

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Find the value of x. Round to the nearest tenth.
nordsb [41]

Step-by-step explanation:

here,,

a=3,b=10,C=120°

c^2=a^2+b^2-2ab cos120°

=(3)^2 +(10)^2 _2 (3)(10)(-1/2) [cos120°=-1/2]

=9+100-(-30)

=109+30

=139

c=(139 )1/2=11.79

c=12

3 0
3 years ago
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