I need to know the answer please

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 108.7-cm and a standard dev

Luden [163]

Let x be the lengths of the steel rods and X ~ N (108.7, 0.6)

To get the probability of less than 109.1 cm, the solution is computed by:

z (109.1) = (X-mean)/standard dev

= 109.1 – 108/ 0.6

= 1.1/0.6

=1.83333, look this up in the z table.

P(x < 109.1) = P(z < 1.8333) = 0.97 or 97%

3 0

4 years ago

Melanie and Michael are on the north bank of a river that is flowing east to west at a speed of 0.5 m/s. They paddle their surf

IRINA_888 [86]

Answer:

total distance travel by them to cross river is 17.3 m

Step-by-step explanation:

Assume A be the initial position of both person and B as apposite point to A

u component of velocity along SOUTH DIRECTION is 4 cos30 = 0.4330 m/s

v component of velocity along SOUTH DIRECTION is 4 cos90 = 0 m/s

total speed will be = 0.4330 + 0 = 0.4330 m/s

time taken $= \frac{width/ of/ river}{speed}$

time taken $= \frac{30}{0.4330} = 69.3 sec$

component of u in downstream direction = 4 cos120 = -0.25 m/s

component of v in downstream direction = 4 cos 0 = 0.5 m/s

total component in downstream will be -0.25 + 0.5 = 0.25

total distance travel by them to cross river is $= 0.25\times 69.3 = 17.3 m$ downstream.

5 0

4 years ago

The range of the function is to because 4x is always positive. On a coordinate plane, an exponential function approaches the x-a

lorasvet [3.4K]

Answer:

The RANGE of the function is

✔ ZERO

to

✔ POSITIVE INFINITY

because 4x is always positive.

PLZ MARK AS BRAINLIEST:):):)

ALSO THANK AND FIVE STARE.

8 0

3 years ago

Read 2 more answers

An object, which is at the origin at time t=0, has initial velocity V0= (-14.0i - 7.0j)m/s and constant acceleration a=(6.0i + 3

sesenic [268]

I am pretty sure the first thing we should do is to integrate acceleration into velocity
And we will have: $a(t) = \ \textless \ 6,3\ \textgreater \$ $v(t) = \ \textless \ (6t+C),(3t+C)\ \textgreater \ ; where -- v(0) = \ \textless \ -14,-7\ \textgreater \$
Then calculate v : $
v(t) = \ \textless \ (6t-14),(3t-7)\ \textgreater \$
As you can see, velocity is zero and none of the objects is moving. It happens when t=7/3 which means we can calculate this in the way we did (integrating) :
 $p(t) = \ \textless \ (3t^2-14t+C) , ((3/2)t^2-7t+C) \ \textgreater \ 
$
The product is p(0) = 0 that makes us to reduce vector function to $p(t) = \ \textless \ (3t^2-14t) , ((3/2)t^2-7t) \ \textgreater \ where t = 7/3$ $p(7/3) = \ \textless \ -49/3 , -49/6 \ \textgreater \$

7 0

4 years ago

Read 2 more answers

What’s the answer to this problem

natta225 [31]

Answer:

247.265

Step-by-step explanation:

8 0

3 years ago